下面上代码: classSolution{public:intminSubArrayLen(ints,vector<int>& nums){intlen = nums.size();if(len ==0)return0;// 数组为空intminlen = INT_MAX;intsum =0;intleft =0;// 滑动窗口的左右边沿intright =-1;while(right < len) {while(sum < s && right < len) sum += nums[++righ...
代码例如以下 classSolution{public:intminSubArrayLen(ints,vector<int>& nums){inti,start,minlength,tempresult; minlength=INT_MAX; start=0; tempresult=0;for(i=start;i<nums.size();i++) { tempresult+=nums[i];if(tempresult>=s) { minlength=min(minlength,i-start+1); tempresult-=nums[start...
Leetcode力扣 209 | 长度最小的子数组 Minimum Size Subarray Sum 2020年11月05日 07:455743浏览·30点赞·11评论 爱学习的饲养员 粉丝:7.0万文章:46 关注 视频讲解 622:17 Leetcode力扣 1-300题视频讲解合集|手画图解版+代码【持续更新ing】 84.4万798 ...
1// 209. Minimum Size Subarray Sum 2// https://leetcode.com/problems/minimum-size-subarray-sum/description/ 3// 4// 滑动窗口的思路 5// 时间复杂度: O(n) 6// 空间复杂度: O(1) 7classSolution{ 8public: 9intminSubArrayLen(ints,vector<int>& nums){ 10 11intl =0, r =-1;// nu...
[Leetcode] 209. Minimum Size Subarray Sum link: https://leetcode.com/problems/minimum-size-subarray-sum/ Solution: 双指针 需要注意左边指针右移次数的判定 TC: O(n) SC: O(1)...LeetCode 209. Minimum Size Subarray Sum LeetCode 209. Minimum Size Subarray Sum Description Given an array ...
[Leetcode] 209. Minimum Size Subarray Sum link: https://leetcode.com/problems/minimum-size-subarray-sum/ Solution: 双指针 需要注意左边指针右移次数的判定 TC: O(n) SC: O(1)...LeetCode 209. Minimum Size Subarray Sum LeetCode 209. Minimum Size Subarray Sum Description Given an array ...
Leetcode 209. Minimum Size Subarray Sum 0 / 0 / 创建于 5年前 / 复盘 没有明确 循环终止条件和循环终止状态定义 需要走几个极端的测试用例 复盘: 对比bobo sir 的定义: 初始l=0 , r=-1 , curMin=len +1 初始化的情况要特殊化,否则判断的代码要复杂许多 总之就是边界都要添加” 哨兵” , 用于...
class Solution { public: int minSubArrayLen(int s, vector<int>& nums) { if(nums.empty()){ return 0; } int i=0; int j=i+1; int sum=nums[i]; int m=nums.size(); int len=m+1; while(j<m){ while(sum<s&&j<m){
https://leetcode.com/problems/minimum-size-subarray-sum/ 题目: n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn't one, return 0 instead. [2,3,1,2,4,3]ands = 7, ...
}if(left == n +1)break; res= min(res, left -i); }returnres == INT_MAX ?0: res; } }; 本文转自博客园Grandyang的博客,原文链接:最短子数组之和[LeetCode] Minimum Size Subarray Sum,如需转载请自行联系原博主。