题意:给一个序列,找出其中一个连续子序列,其和大于s但是所含元素最少。返回其长度。0代表整个序列之和均小于s。 思路:O(n)的方法容易想。就是扫一遍,当子序列和大于s时就一直删减子序列前面的一个元素,直到小于s就停下,继续累加后面的。 AC代码
1.sum>=s,更新答案,并且i++,注意i==j的情况要i++,j++ 2.sum<s,说明现在和还不够,所以j++ 1classSolution {2public:3intminSubArrayLen(ints, vector<int>&nums) {4intlen=nums.size();5if(len==0)return0;6inti=0,j=0;7intsum=nums[0];8intans=INT_MAX;9while(j<len){10if(sum<s)...
代码: func subarraySum(nums []int, k int) int { sum, count := 0, 0 m := map[int]int{} m[0] = 1 for i := 0; i < len(nums); i++ { sum += nums[i] if _, ok := m[sum-k]; ok { count += m[sum-k] } m[sum] += 1 } return count }发布...
public int minSubArrayLen(int s, int[] nums) { if (nums.length == 0) return 0; int minLen = Integer.MAX_VALUE, start = 0, end = 0; int sum = 0; while (end < nums.length) { while (sum < s && end < nums.length) { sum += nums[end++];//若不满足 则扩大范围 } while...
func checkSubarraySum(nums []int, k int) bool { m := len(nums) if m < 2 { return false } mp := map[int]int{0: -1} remainder := 0 for i, num := range nums { remainder = (remainder + num) % k if prevIndex, has := mp[remainder]; has { if i-prevIndex >= 2 { ...
Given an array of npositiveintegers and a positive integer s, find theminimal lengthof acontiguous subarrayof which thesum ≥ s. If there isn’t one, return 0 instead. 说人话: 给定一个含有 n 个正整数的数组和一个正整数 s ,找出该数组中满足其和 ≥ s 的长度最小的连续子数组,并返回其长...
Leetcode力扣 209 | 长度最小的子数组 Minimum Size Subarray Sum 2020年11月05日 07:455743浏览·30点赞·11评论 爱学习的饲养员 粉丝:7.0万文章:46 关注 视频讲解 622:17 Leetcode力扣 1-300题视频讲解合集|手画图解版+代码【持续更新ing】 84.4万798 ...
代码运行次数:0 运行 AI代码解释 classSolution:defmaxSubArray(self,nums):""":type nums:List[int]:rtype:int""" sum=0max=nums[0]foriinnums:ifsum+i>0and sum>=max:sum+=i max=sumreturnmax C实现 C语言实现上, 我使用了#defineMAX来比较两数的最大值, 代替了直接使用三目运算符的做法, 从8ms...
Can you solve this real interview question? Continuous Subarray Sum - Given an integer array nums and an integer k, return true if nums has a good subarray or false otherwise. A good subarray is a subarray where: * its length is at least two, and * t
Can you solve this real interview question? Continuous Subarray Sum - Given an integer array nums and an integer k, return true if nums has a good subarray or false otherwise. A good subarray is a subarray where: * its length is at least two, and * t