You are given an integer arraynums. The range of a subarray ofnumsis the difference between the largest and smallest element in the subarray. Returnthe sum of all subarray ranges ofnums. A subarray is a contiguous non-empty sequence of elements within an array. Example 1: Input: nums = [...
Given the array nums consisting of n positive integers. You computed the sum of all non-empty continous subarrays from the array and then sort them in non-decreasing order, creating a new array of n * (n + 1) / 2 numbers. Return the sum of the numbers from index left to index righ...
Leetcode__1508. Range Sum of Sorted Subarray Sums 这一题是一道十分典型的二分查找与双指针的使用,题目的大意是,给出一个数组numsnums, 我们可以通过该数组得到子数组, 子数组的大小从 1 到nn, 因此有n(n+1)2n(n+1)2个不同的子数组, 然后我们要求这些子数组的和, 然后对这些子数组的和进行排序, 求...
第一种是prefix sum + 双指针。 例如Minimum Size Subarray Sum - LeetCode: Given an array of n positive integers and a positive integers, find the minimal length of a contiguous subarray of which the sum ≥s. If there isn't one, return 0 instead. 用O(N)时间得到一个prefix sum array,可...
[leetcode] 209. Minimum Size Subarray Sum Description Given an array of n positive integers and a positive integer s, find the minimal length of a contiguous subarray of which the sum ≥ s. If there isn’t one, return 0 instead.
代码运行次数:0 运行 AI代码解释 classSolution:defmaxSubArray(self,nums:List[int])->int:n=len(nums)dp=[0]*n dp[0]=nums[0]maximum=dp[0]foriinrange(1,n):dp[i]=max(dp[i-1]+nums[i],nums[i])maximum=max(maximum,dp[i])returnmaximum...
Given an array of integers A, find the sum of min(B), where B ranges over every (contiguous) subarray of A. Since the answer may be large, return the answer modulo 10^9 + 7. Example 1: Input: [3,1,2,4] Output: 17 Explanation: Subarrays are [3], [1], [2], [4], [3,...
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we're essentially looking for at everyiis the largestjsuch that it's prefix sum is <= pref[i] — k (the largest j so that we can cut off as much of the array as possible). This problem can be solved with a segment tree that handles point updates and stores the max on a range...
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