public int numSubarraysWithSum(int[]A,intS) { return atMost(A,S) - atMost(A,S- 1); } private int atMost(int[]A,intS) { if (S< 0) return 0; int res = 0, n =A.length; for (inti= 0,j= 0;j<n; ++j) {S-=A[j]; while (S< 0)S+=A[i++]; res += j - i...
leetcode 930. Binary Subarrays With Sum This remains me of some 'subarray count' type problems….. classSolution{publicintnumSubarraysWithSum(int[] A,intS){int[] ps =newint[A.length +1]; ps[0] =1;intsum=0;intret=0;for(intv: A) { sum += v;if(sum - S >=0) { ret +=...
public int numSubarraysWithSum(int[] A, int S) { if (A.length == 0) return 0; int result = 0; int[] sumOne = new int[A.length]; int st = 0; int ed = 0; sumOne[0] = A[0] == 1 ? 1 : 0; for (int i = 1; i < A.length; i++) { sumOne[i] = A[i] =...
第一种是prefix sum + 双指针。 例如Minimum Size Subarray Sum - LeetCode: Given an array of n positive integers and a positive integers, find the minimal length of a contiguous subarray of which the sum ≥s. If there isn't one, return 0 instead. 用O(N)时间得到一个prefix sum array,可...
D[0] exists in our deque, it means that before B[i], we didn’t find a subarray whose sum at least K. B[i] is the first prefix sum that valid this condition. In other words, A[D[0]] ~ A[i-1] is the shortest subarray starting at A[D[0]] with sum at least K. ...
树中距离之和 Sum of Distances in Tree 132 -- 10:09 App LeetCode力扣 493. 翻转对 Reverse Pairs 136 -- 7:44 App LeetCode力扣 56. 合并区间 Merge Intervals 389 -- 11:26 App Python每日一练-字典数组练习-歌唱比赛名次 156 -- 7:23 App LeetCode力扣 118. 杨辉三角 Pascal's Triangle...
#LeetCode# I have solved Subarray Sum Equals K. Come and join the fun! Day 22 -记录区间值 -map 半天才想明白 http://t.cn/A6wnRfJD
1186 Maximum Subarray Sum with One Deletion 删除一次得到子数组最大和 Description: Given an array of integers, return the maximum sum for a non-empty subarray (contiguous elements) with at most one element deletion. In other words, you want to choose a subarray and optionally delete one element...
package leetcode._209;publicclassSolution{publicintminSubArrayLen(ints,int[]nums){intl=0,r=-1;intwindowSum=0;intwindowLength=nums.length+1;while(l<nums.length){if(r+1<nums.length&&windowSum<s){r++;windowSum+=nums[r];}else{windowSum-=nums[l];l++;}if(windowSum>=s){windowLength=Ma...
leetcode974. Subarray Sums Divisible by K Given an array A of integers, return the number of (contiguous, non-empty) subarrays that have a sum divisible by K. Example 1: Note: 给定一个集合,求这个集合中子集的个数,其中对子集的要求是子集中元素的和能被k整除。 记数组pre[i+1]表示前 i...