numsand an integerthe number of non-emptysubarrayswith a sumgoal. Asubarrayis a contiguous part of the array. Example 1: Input:nums = [1,0,1,0,1], goal = 2Output:4Explanation:The 4 subarrays are bolded and unde
leetcode 930. Binary Subarrays With Sum This remains me of some 'subarray count' type problems….. classSolution{publicintnumSubarraysWithSum(int[] A,intS){int[] ps =newint[A.length +1]; ps[0] =1;intsum=0;intret=0;for(intv: A) { sum += v;if(sum - S >=0) { ret +=...
public int numSubarraysWithSum(int[]A,intS) { return atMost(A,S) - atMost(A,S- 1); } private int atMost(int[]A,intS) { if (S< 0) return 0; int res = 0, n =A.length; for (inti= 0,j= 0;j<n; ++j) {S-=A[j]; while (S< 0)S+=A[i++]; res += j - i...
public int numSubarraysWithSum(int[] A, int S) { if (A.length == 0) return 0; int result = 0; int[] sumOne = new int[A.length]; int st = 0; int ed = 0; sumOne[0] = A[0] == 1 ? 1 : 0; for (int i = 1; i < A.length; i++) { sumOne[i] = A[i] =...
D[0] exists in our deque, it means that before B[i], we didn’t find a subarray whose sum at least K. B[i] is the first prefix sum that valid this condition. In other words, A[D[0]] ~ A[i-1] is the shortest subarray starting at A[D[0]] with sum at least K. ...
第一种是prefix sum + 双指针。 例如Minimum Size Subarray Sum - LeetCode: Given an array of n positive integers and a positive integers, find the minimal length of a contiguous subarray of which the sum ≥s. If there isn't one, return 0 instead. 用O(N)时间得到一个prefix sum array,可...
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简单思考后我们发现,只要得到子数组subarray{0, i}和sum_i子数组subarray{0, j}的和sum_j,那么子数组subarray{i, j}的和sum就等于sum_j - sum_i + nums[i](其中0 <= i <= j < n),而且所有subarray{0, i}的和的值都可以通过预处理原数组在 O(n) 时间内得到。 根据以上逻辑,可以得到优化的...
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package leetcode._209;publicclassSolution{publicintminSubArrayLen(ints,int[]nums){intl=0,r=-1;intwindowSum=0;intwindowLength=nums.length+1;while(l<nums.length){if(r+1<nums.length&&windowSum<s){r++;windowSum+=nums[r];}else{windowSum-=nums[l];l++;}if(windowSum>=s){windowLength=Ma...