You are given an integer arraynums. The range of a subarray ofnumsis the difference between the largest and smallest element in the subarray. Returnthe sum of all subarray ranges ofnums. A subarray is a contiguous non-empty sequence of elements within an array. Example 1: Input: nums = [...
Can you solve this real interview question? Maximum Sum of Two Non-Overlapping Subarrays - Given an integer array nums and two integers firstLen and secondLen, return the maximum sum of elements in two non-overlapping subarrays with lengths firstLen and
[leetcode] 1508. Range Sum of Sorted Subarray Sums Description Given the array nums consisting of n positive integers. You computed the sum of all non-empty continous subarrays from the array and then sort them in non-decreasing order, creating a new array of n * (n + 1) / 2 numbers...
Github 同步地址: https://github.com/grandyang/leetcode/issues/907 参考资料: https://leetcode.com/problems/sum-of-subarray-minimums/ https://leetcode.com/problems/sum-of-subarray-minimums/discuss/170857/One-stack-solution https://leetcode.com/problems/sum-of-subarray-minimums/discuss/222895/Ja...
LeetCode53 Maximum sum of subarray classic dp: dp[i] represents the maximum sum of subarray which ends in nums[i], and dp[i] = Math.max(nums[i], dp[i - 1] + nums[i]). and since we have to include nums[i] due to it’s on the defination of dp[i], and when dp[i-1]<...
Can you solve this real interview question? Binary Subarrays With Sum - Given a binary array nums and an integer goal, return the number of non-empty subarrays with a sum goal. A subarray is a contiguous part of the array. Example 1: Input: nums =
3011. 判断一个数组是否可以变为有序 Find if Array Can Be Sorted 力扣 LeetCode 题解 07:02 2974. 最小数字游戏 Minimum Number Game 力扣 LeetCode 题解 02:29 2972. 统计移除递增子数组的数目 II Count the Number of Incremovable Subarrays 力扣 LeetCode 题解 12:00 2970. 统计移除递增子数组...
LeetCode 209: Minimum Size Subarray Sum(长度最小的子数组) Q:Given an array of n positive integers and a positive integer s, find the minimal length of a contiguous subarray of which the sum ≥ s. If there isn't one, return 0 instead. ...
package leetcode._209;publicclassSolution{publicintminSubArrayLen(ints,int[]nums){intl=0,r=-1;intwindowSum=0;intwindowLength=nums.length+1;while(l<nums.length){if(r+1<nums.length&&windowSum<s){r++;windowSum+=nums[r];}else{windowSum-=nums[l];l++;}if(windowSum>=s){windowLength=...
funcmaximumSubarraySum(nums[]int,kint)int64{ ans:=math.MinInt minS:=map[int]int{} sum:=0 for_,x:=rangenums{ s,ok:=minS[x+k] ifok{ ans=max(ans,sum+x-s) } s,ok=minS[x-k] ifok{ ans=max(ans,sum+x-s) } s,ok=minS[x] ...