简化写法,直接递归原函数isSameTree,首先:① 取消子函数dfs ② 无需分别判断 node1 & node2 的NULL情况 classSolution {public:boolisSameTree(TreeNode* p, TreeNode*q) {if(p&&q)//p & q 均有值return(p->val==q->val && isSameTree(p->left,q->left) && isSameTree(p->right,q->right))...
迭代版: 1publicclassSolution {2publicbooleanisSameTree(TreeNode p, TreeNode q) {3Queue<TreeNode> queueP =newLinkedList<TreeNode>();4Queue<TreeNode> queueQ =newLinkedList<TreeNode>();5TreeNode p1, p2;6queueP.add(p);7queueQ.add(q);8while(!queueP.isEmpty() && !queueQ.isEmpty())...
通过的Java代码如下: /*** Definition for a binary tree node.* public class TreeNode {* int val;* TreeNode left;* TreeNode right;* TreeNode(int x) { val = x; }* }*/classSolution{publicbooleanisSameTree(TreeNodep,TreeNodeq){if(p==null&&q==null){returntrue;}elseif(p==null&&q!
100. 相同的树 - 给你两棵二叉树的根节点 p 和 q ,编写一个函数来检验这两棵树是否相同。 如果两个树在结构上相同,并且节点具有相同的值,则认为它们是相同的。 示例 1: [https://assets.leetcode.com/uploads/2020/12/20/ex1.jpg] 输入:p = [1,2,3], q = [1,2,
【leetcode】比较两棵二叉树是否相同(Same Tree),题目要求如下:Giventwobinarytrees,writeafunctiontocheckiftheyareequalornot.Twobinarytreesareconsideredequaliftheyarestructurallyidenticalandthenodeshavethesamevalue.
[Leetcode]-Same Tree Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. Hide Tags :Tree 。Depth-first Search...
= left # self.right = right class Solution: def isSameTree(self, p: Optional[TreeNode], q: Optional[TreeNode]) -> bool: # 都是空结点,则当前子树相同,直接返回 true if not p and not q: return True # 如果当前结点都值不同,则当前子树不同,直接返回 false if not p or not q or p....
题目Same Tree Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 分析 判断两个二叉树是否相等,只要每个都遍历(前,中,后,层次)一下进行对比即可. 笼统的我们也...
题目链接[https://leetcode-cn.com/problems/same-tree/]tag: Easy; DFS; BFS; question: Given ...
1519. 子树中标签相同的节点数 - 给你一棵树(即,一个连通的无环无向图),这棵树由编号从 0 到 n - 1 的 n 个节点组成,且恰好有 n - 1 条 edges 。树的根节点为节点 0 ,树上的每一个节点都有一个标签,也就是字符串 labels 中的一个小写字符(编号为 i 的 节点的标签就