return isSameTree(p->left,q->left) && isSameTree(p->right,q->right); } };
[LeetCode] Same Tree http://oj.leetcode.com/problems/same-tree/1 class Solution { 2 public: 3 bool isSameTree(TreeNode *p, TreeNode *q) { 4 // IMPORTANT: Please reset any member data you declared, as 5 // the same Solution instance will be reused for each test case....
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right (right) {} * }; */ classSolution{ public: boolisSameTree(TreeNode*p,TreeNode*q) { ...
AI代码解释 classSolution{publicbooleanisSameTree(TreeNode p,TreeNode q){if(p==null)returnq==null;returnq!=null&&p.val==q.val&&isSameTree(p.left,q.left)&&isSameTree(p.right,q.right);}} 3、时间复杂度 时间复杂度 :O(min(m,n)) 其中m和n分别是两个二叉树的节点数,对两个二叉树同事进...
/*** Definition for a binary tree node.* public class TreeNode {* int val;* TreeNode left;* TreeNode right;* TreeNode(int x) { val = x; }* }*/classSolution{publicbooleanisSameTree(TreeNodep,TreeNodeq){if(p==null&&q==null){returntrue;}elseif(p==null&&q!=null){returnfalse;...
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: bool isSameTree(TreeNode* p, TreeNode* q) { if(!p && !q) { ...
TreeNode(int x) : val(x), left(NULL), right(NULL) {} }; class Solution { public: bool isSameTree(TreeNode *p, TreeNode *q) { if (p == NULL && q == NULL) return true; // p和q不同一时候到达叶节点,则剪枝 else if ((p != NULL && q == NULL) || (p == NULL && q...
Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 思路:太简单! AI检测代码解析 boolisSameTree(TreeNode *p, TreeNode *q) {if(p == NULL && q == NULL...
isSameTree(q.left, p.left) \ and self.isSameTree(q.right, p.right) # 如果p和q均为空 if not p and not q: return True return False 使用递归的方法使理解起来很容易,逻辑上也相对简单。 Symmetric Tree 题目:Symmetric Tree Given a binary tree, check whether it is a mirror of itself (...
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right (right) {} * }; */ class Solution { public: bool isSameTree(TreeNode* p, TreeNode* q) { } }; 已存储 行1,列 1 运行和提交...