* TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * };*/classSolution {public:boolisSameTree(TreeNode *p, TreeNode *q) {if(!p && !q)returntrue;elseif(!p &&q)returnfalse;elseif(p && !q)returnfalse;else{if(p->val != q->val)returnfalse;elseret...
* struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: bool isSameTree(TreeNode* p, TreeNode* q) { if(!p && !q) { return true; } else if(p && q) { return ...
通过的Java代码如下: /*** Definition for a binary tree node.* public class TreeNode {* int val;* TreeNode left;* TreeNode right;* TreeNode(int x) { val = x; }* }*/classSolution{publicbooleanisSameTree(TreeNodep,TreeNodeq){if(p==null&&q==null){returntrue;}elseif(p==null&&q!
给定两个树,判断两个数是否相同 Solution1: DFS (Code will be neat and simple) code 1classSolution {2publicbooleanisSameTree(TreeNode p, TreeNode q) {3if(p ==null&& q ==null)returntrue;4if(p ==null|| q ==null)returnfalse;56if(p.val ==q.val){7returnisSameTree(p.left, q.left...
TreeNode(int x) : val(x), left(NULL), right(NULL) {} }; class Solution { public: bool isSameTree(TreeNode *p, TreeNode *q) { if (p == NULL && q == NULL) return true; // p和q不同一时候到达叶节点,则剪枝 else if ((p != NULL && q == NULL) || (p == NULL && q...
Given the roots of two binary treespandq, write a function to check if they are the same or not. Two binary trees are considered the same if they are structurally identical, and the nodes have the same value. Example 1: Input:p = [1,2,3], q = [1,2,3]Output:true ...
class Solution { public: bool isSameTree(TreeNode* p, TreeNode* q) { queue<TreeNode*> Q1,Q2; TreeNode *pCurr,*qCurr; int flag = true; if(p != NULL && q != NULL) { Q1.push(p); Q2.push(q); while(!Q1.empty() && !Q2.empty()) ...
1519. 子树中标签相同的节点数 - 给你一棵树(即,一个连通的无环无向图),这棵树由编号从 0 到 n - 1 的 n 个节点组成,且恰好有 n - 1 条 edges 。树的根节点为节点 0 ,树上的每一个节点都有一个标签,也就是字符串 labels 中的一个小写字符(编号为 i 的 节点的标签就
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {} * }; */class Solution{public:boolisSameTree(TreeNode*p,TreeNode*q){// 递归,深度优先搜索if(!p&&!q)returntrue;if(!p&&q)returnfalse;if(p&&!q)returnfalse;if(p->val!=q->val)returnfalse...
same-tree //先序遍历递归classSolution{public:boolisSameTree(TreeNode*p,TreeNode*q){if(!p&&!q)returntrue;if(!p||!q)returnfalse;returnp->val==q->val&&isSameTree(p->left,q->left)&&isSameTree(p->right,q->right);}};//后序遍历递归,会比先序遍历的快,因为从下到上classSolution{...