You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplicate exists in the array. KEY WORDS: [Rotated sorted array] [find target] [no duplicate] publicintsearch(int[] nums,inttarget) {if(nums ==null|| nums.length...
LeetCode 33 Search in Rotated Sorted Array [binary search] 给出排序好的一维无重复元素的数组,随机取一个位置断开,把前半部分接到后半部分后面,得到一个新数组,在新数组中查找给定数的下标,如果没有,返回 1。时间复杂度限制$O(log_2n)$
Search in Rotated Sorted Array I && II Leetcode 对有序数组进行二分查找(下面仅以非递减数组为例): 1. int binarySort(int A[], int lo, int hi, int target) 2. { 3. while(lo <= hi) 4. { 5. int mid = lo + (hi - lo)/2; 6. if(A[mid] == target) 7. return mid; 8....
搜索旋转排序数组 Search in Rotated Sorted Array II There is an integer array nums sorted in non-decreasing order (not necessarily with distinct values). Before being passed to your function, nums is rotated at an unknown pivot index k (0 <= k < nums.length) such that the resulting array...
package day_6;publicclassSearchInRotatedSortedArray{publicintsearch(int[]nums,int target){intcount=nums.length;if(count==0)return-1;if(count==1)if(nums[0]==target)return0;elsereturn-1;intleft=0;intright=count-1;while(left<=right){// 高级版的二分查找int mid=(left+right)/2;System.ou...
Medium,Binary Search Question 接Find Minimum in Rotated Sorted Array, 假设有重复数字。 Solution 解法依然是二分搜索,不过多了一种情况要考虑。 classSolution(object):deffindMin(self,nums):""" :type nums: List[int] :rtype: int """L,R=0,len(nums)-1whileL<Randnums[L]>=nums[R]:M=(L+...
!谢谢大家了! 分享1赞 leetcode吧 chipgenius Search in Rotated SortedArray直接一遍也可以通过 分享1赞 sdl吧 kkk2ooo1 我想写一个旋转图片的代码,但是旋转的时候会出问题// 因为旋转后的rotatedRobot比原始robot的surface要大,所以有了下面的代码重新确定在screen上位置,但是执行还是有问题,请高手帮帮忙指点...
81. Search in Rotated Sorted Array II There is an integer arraynumssorted in non-decreasing order (not necessarily withdistinctvalues). Before being passed to your function,numsisrotatedat an unknown pivot indexk(0 <= k < nums.length) such that the resulting array is[nums[k], nums[k+1...
LeetCode—108. Convert Sorted Array to Binary Search Tree 题目 https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/description/ 将一个递增数组转化为平衡二叉搜索树。平衡二叉搜索树首先是一个二叉搜索树,其次要求每一个节点的左右...[...
publicclassSolution{publicintsearch(int[]array,inttarget){// corner caseif(array==null||array.length==0){return-1;}intleft=0,right=array.length-1;intend=array[right];while(left<right-1){intmid=left+(right-left)/2;if(array[mid]<=end){if(target<=end&&array[mid]<=target){left=mid;...