Find Minimum in Rotated Sorted Array II (cpp) 题目和测试用例略233 本题作为153题的升级版,难点在于数组中的数可能有重复的。 这种问题很容易想到用二分搜索的思想来解决(毕竟如果暴力求解时间复杂度只有O(N),比O(N)小的就是O(logN)了233)。设l是考虑的左边界,r是右边界,m是计算出的中点坐标。 下
Follow up for "Search in Rotated Sorted Array": What ifduplicatesare allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 解法:同旋转数组查找I,本题也使用二分查找,只是在nums[mid]和nums[right](或者nums[right])...
Write a function to determine if a given target is in the array. 解题思路: 这题与上一题Search in Rotated Sorted Array略有不同,数组中允许重复元素。粗粗一想,不太容易判断重复元素会给我们带来什么样的影响,还有到底重复元素出现在什么地方,会给我们带来关键性的影响?这是这道题的两个关键问题。那么...
// Search in Rotated Sorted Array II// Time Complexity: O(n),Space Complexity: O(1)classSolution{public:boolsearch(constvector<int>&nums,inttarget){intfirst=0,last=nums.size();while(first!=last){constintmid=first+(last-first)/2;if(nums[mid]==target)returntrue;if(nums[first]<nums[m...
This is a follow up problem toSearch in Rotated Sorted Array, wherenumsmay contain duplicates. Would this affect the run-time complexity? How and why? 题目大意 假设按照升序排序的数组在预先未知的某个点上进行了旋转。( 例如,数组 [0,0,1,2,2,5,6] 可能变为 [2,5,6,0,0,1,2] )。
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Write a function to determine if a given target is in the array. The array may contain duplicates. ...
[ 4 5 6 7 1 2 3] ,如果 target = 5,那么数组可以看做 [ 4 5 6 7 inf inf inf ]。 [ 4 5 6 7 1 2 3] ,如果 target = 2,那么数组可以看做 [ -inf -inf - inf -inf 1 2 3]。 和解法一一样,我们每次只关心 mid 的值,所以 mid 要么就是 nums [ mid ],要么就是 inf 或者 -...
int bs(int *nums,int numsSize,int target)//bs为二分搜索函数 { int low = 0; int high = numsSize - 1; while(low <= high) { int medium = (low+high )/2; if(nums[medium] == target)return medium; else if(nums[medium] > target)high = medium - 1; else low = medium+1; }...
题目链接 https://leetcode.com/problems/search-in-rotated-sorted-array-ii/ 解题思路 先找到数组被rotate...
81. Search in Rotated Sorted Array II Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e.,[0,0,1,2,2,5,6]might become[2,5,6,0,0,1,2]). You are given a target value to search. If found in the array returntrue, otherwise re...