}; 二:Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may ...
returnfalse; boolresult=searchD(nums, target, 0, size-1); returnresult; } };
publicintsearch(int[]nums,inttarget){intstart=0;intend=nums.length-1;//找出最小值的数组下标/* while (start < end) {int mid = (start + end) / 2;if (nums[mid] > nums[end]) {start = mid + 1 ;} else {end = mid;}}int bias = start;*///找出最大值的数组下标while(start<end...
一、33. Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0124567might become4567012). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplicate exists...
You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplicate exists in the array. 本题难度hard。利用二分查找法即可。分别使用迭代和递归实现。 【题意】 题目的意思是对rotated后的array,利用它的局部有序性来找到target,返回其...
Search in Rotated Sorted Array 描述 Suppose a sorted array is rotated at some pivot unknown to you beforehand. 2.1 数组 5 (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return ...
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33. Search in Rotated Sorted Array 寻找旋转排序数组 There is an integer array nums sorted in ascending order (with distinct values). 一个升序排序的整数数组 Prior to being passed to your function, nums is possibly rotated at an unknown pivot index k (1 <= k < nums.length) such that th...
先找到数组被rotated的位置如果有的话。 确定好位置之后再在排序的数据区间内查找元素。 代码 class Solution{public:intsearch(vector<int>&nums,inttarget){if(nums.size()==0){return-1;}intpos=findPos(nums,0,nums.size()-1);if(pos==-1){returnfindVal(nums,0,nums.size()-1,target);}if(targ...
Question: Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. ...