First comes the link to the old original problem:Search in Rotated Sorted Array. The first solution wasn't quite satisfactory, with a time complexity of O(n). First we find out the rotation offset with O(n) time, and do a rotated binary search with another O(log(n)) time. Space c...
Constraints: 1 <= nums.length <= 5000 -104<= nums[i] <= 104 numsis guaranteed to be rotated at some pivot. -104<= target <= 104 Follow up:This problem is similar toSearch in Rotated Sorted Array, butnumsmay containduplicates. Would this affect the runtime complexity? How and why...
What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 本题难度Medium。 【复杂度】 时间O(N) 空间 O(1) 【思路】 本题是Search in Rotated Sorted Array的变形。在Search in Rotated Sorted A...
LeetCode—108. Convert Sorted Array to Binary Search Tree 题目 https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/description/ 将一个递增数组转化为平衡二叉搜索树。平衡二叉搜索树首先是一个二叉搜索树,其次要求每一个节点的左右...[...
0026. Remove Duplicates From Sorted Array 0027. Remove Element 0028. Find the Index of the First Occurrence in a String 0029. Divide Two Integers 0030. Substring With Concatenation of All Words 0031. Next Permutation 0032. Longest Valid Parentheses 0033. Search in Rotated Sorted Array 0034. ...
This is a follow up problem toSearch in Rotated Sorted Array, wherenumsmay contain duplicates. Would this affect the run-time complexity? How and why? 在旋转有序数组中搜索二。 这题跟33题求的一样,多一个条件是input里面有重复数字。依然是用二分法做,但是worst case很可能会到O(n);而且其中一开...
function<int(int,int)> binary_search = [&nums](inttarget,intindex) ->int{if(nums.empty())return-1;intlow =index, high = nums.size() -1+index;while(low <=high) {intmid = (high-low)/2+low;intvalue = nums[mid%nums.size()];if(target < value) high = mid -1;elseif(target...
0067-Add-Binary 0069-Sqrt-x 0070-Climbing-Stairs 0072-Edit-Distance 0073-Set-Matrix-Zeroes 0075-Sort-Colors 0076-Minimum-Window-Substring 0077-Combinations 0079-Word-Search 0080-Remove-Duplicates-from-Sorted-Array-II 0082-Remove-Duplicates-from-Sorted-List-II 0086-Partitio...
LeetCode—108. Convert Sorted Array to Binary Search Tree 题目 https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/description/ 将一个递增数组转化为平衡二叉搜索树。平衡二叉搜索树首先是一个二叉搜索树,其次要求每一个节点的左右...[...
is still to use invariants. We setlto be the left pointer andrto be the right pointer. Since duplicates exist, the invatiant isnums[l] >= nums[r](if it does not hold, thennums[l]will simply be the minimum). We then begin binary search by comparingnums[l], nums[r]withnums[mid]...