Could the input string contain leading or trailing spaces? Yes. However, your reversed string should not contain leading or trailing spaces. How about multiple spaces between two words? Reduce them to a single space in the reversed string. SOLUTION 1: 1. 先处理原字符串: 使用strim把前后的空格...
题目地址:https://oj.leetcode.com/problems/reverse-words-in-a-string/ 算法:先把字符串分成一个一个word放在vector里面,然后在按逆序存入原来的字符串里。代码: 1classSolution {2public:3voidreverseWords(string&s) {4vector<string> words =split(s);5s.clear();6vector<string>::reverse_iterator iter...
vector<string> words; int start = int(s.length() - 1); //从后往前遍历 for (int i = start; i >= 0; --i) { if (s[i] == ' ') { words.push_back(s.substr(i + 1, start - i)); if (i != 0) start = i - 1; } } s.clear(); size_t size = words.size(); fo...
For C programmers: Try to solve it in-place in O(1) space. 对于Java实现,直接分割字符串然后逆序即可。 代码如下: public class Solution { public String reverseWords(String s) { if(s==null || s.length()<=0) return s; s=s.trim(); String []res=s.split("\\s+"); if(res.length<...
原题链接https://leetcode.com/problems/reverse-words-in-a-string/ Given an input string, reverse the string word by word. Example 1: Input: "the sky is blue" Output: "blue is sky the" Example 2: Input: " hello world! " Output: "world! hello" ...
参考LeetCode #189 Rotate Array 旋转数组 先将整个字符串反转 再按空格反转每个单词并去掉额外的空格 时间复杂度O(n), 空间复杂度O(n) 代码: C++: class Solution{public:stringreverseWords(string s){stringstream ss;string result="",temp;ss<<s;while(ss>>temp)result=" "+temp+result;if(result.size...
Can you solve this real interview question? Reverse Words in a String - Given an input string s, reverse the order of the words. A word is defined as a sequence of non-space characters. The words in s will be separated by at least one space. Return a s
The input string does not contain leading or trailing spaces. The words are always separated by a single space. Follow up: Could you do it in-place without allocating extra space? Solution class Solution { public void reverseWords(char[] str) { ...
class Solution { public: void ReverseWord(string &s,int p, int q){ while(p < q){ char t = s[p] ; s[p++] = s[q] ; s[q--] = t ; } } void reverseWords(string &s) { bool flag; int p = 0; int q = 0; string str = ""; ...
[leetcode]Reverse Words in a String 2014-03-09 20:29 − leetcode新题,好久没更新了的感觉 class Solution { public: void reverseWords(string &s) { vector<string> res; int i = 0; int len = s... 1957 0 939 LeetCode: Reverse Words in a String 2014-07-27 21:07 − Leet...