voidreverseWords(string &str) { if(str.size()==0)return; autobeg = str.begin(); autoend = str.end(); reverse(beg,end); for(autospace = beg; space != end; ) { space = std::find(beg,end,' '); reverse(beg,space); beg = space + 1; } } 别人家的代码 解法二:类似栈的思...
http://oj.leetcode.com/problems/reverse-words-in-a-string/ Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". LeetCode OJ supports Python now! The solution for this problem is extremely easy... What you nee...
problem 557. Reverse Words in a String III solution1:字符流处理类istringstream. class Solution { public: string reverseWords(string s) { string ans = "", t = ""; istringstream is(s);// while(is >> t) { reverse(t.begin(), t.end()); ans += t + " ";//err. ...
https://leetcode-cn.com/problems/reverse-words-in-a-string-iii/ Given a string s, reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. 给定一个字符串 s ,你需要反转字符串中每个单词的字符顺序,同时仍保留空格和单词的初始顺序。
//#105Description: Construct Binary Tree from Preorder and Inorder Traversal | LeetCode OJ 解法1:理解前序、中序、后序的性质,然后用哈希表快速查找各元素的位置,以达到O(N)时间重建的目的。 // Solution 1: Understand the properties of pre-order, inorder and post-order traversal. Use a hash ta...
【题目】Given inorder and postorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 【解答】初看没啥头绪,不过草稿纸上随便画了一个简单的二叉树:1 / 2 3 / 4 5 6 7, 它的中序遍历是:4 2 5 1 6 3 7 它的后序遍历是:...
190Reverse BitsC 189Rotate ArrayC 188Best Time to Buy and Sell Stock IV 187Repeated DNA Sequences 186Reverse Words in a String II☢ 179Largest NumberC 174Dungeon Game 173Binary Search Tree IteratorC++ 172Factorial Trailing ZeroesC 171Excel Sheet Column NumberC ...
输入:s = "a good example" 输出:"example good a" 解释:如果两个单词间有多余的空格,反转后的字符串需要将单词间的空格减少到仅有一个。 提示: 1 <= s.length <= 104 s 包含英文大小写字母、数字和空格 ' ' s 中至少存在一个 单词 进阶:如果字符串在你使用的编程语言中是一种可变数据类型,请尝试...
class Solution { public String reverseWords(String s) { StringBuilder sb=new StringBuilder(); if(s==null||s.length()<=0) return ""; int endLeft=s.length()-1; in Java 0 317 0沈乔维 ・ 2020.02.02 java版本的简单做法 public String reverseWords(String s) { String[] words = new Stri...
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