因此in-place方法很简单,先把整个字符串反转,然后依次把字符串中的每个单词再反转一次。 1classSolution {2public:3voidreverseWords(string&s) {4intl =0, r = s.size() -1;5while(l <r)6swap(s[l++], s[r--]);7for(inti =0, n = s.size(); i <n;)8{9for(r = i +1; r < n &...
Leetcode: Reverse Words in a String II Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters. The input string does not contain leading or trailing spaces and the words are always separated by a single space. For example, Given ...
Leetcode: Reverse Words in a String II Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters. The input string does not contain leading or trailing spaces and the words are always separated by a single space. For example, Given ...
return "blue is sky the". Could you do itin-placewithout allocating extra space? classSolution {public://无需额外空间开销//反转整个字符串, 再反转每个单词voidreverseWords(string&s) {if(s.length()<1)return;inti=0,j=s.length()-1;//去开头结尾的空格while(s[i]==''&&i<s.length()) {...
链滴Reverse Words in a String III--leetcode 作者:moloee 原文链接:https://ld246.com/article/1509275957069 来源网站:链滴 许可协议:署名-相同方式共享 4.0 国际 (CC BY-SA 4.0) 题目 Given a string, you need to reverse the order of characters in each word within a sentence whi e still ...
Can you solve this real interview question? Reverse Words in a String III - Given a string s, reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: s = "Let's take
输入:s = "a good example" 输出:"example good a" 解释:如果两个单词间有多余的空格,反转后的字符串需要将单词间的空格减少到仅有一个。 提示: 1 <= s.length <= 104 s 包含英文大小写字母、数字和空格 ' ' s 中至少存在一个 单词 进阶:如果字符串在你使用的编程语言中是一种可变数据类型,请尝试...
My code: publicclassSolution{publicvoid reverseWords(char[]s){if(s==null||s.length==0)return;intbegin=s.length-1;intend=s.length-1;while(end>=0){char curr=s[end];if(begin==end){if(curr==' '){end--;begin--;}else{end--;}}else{if(curr==' '){reverse(s,end+1,begin);end...
Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters. The input string does not contain leading or trailing spaces and the words are always separated by a single space. For example, ...
void reverseWords(string &s) { s = removeDuplicateSpace(s); int begin = 0; int end = 0; while(end < s.size()){ if(s[end] == ' '){ swapString(s, begin, end - 1); begin = end+1; end = begin; } else{ end++; } } swapString(s, begin, end - 1)...