最intuitive的办法就是直接把integer化成string,然后变成list。这里如果化成string,会有溢出的问题,比如integer是1534236469,这个数字反过来就是个很大的数,溢出了,必须返回0. 如果是直接用int计算的,那就会自动溢出得到正确结果。这里如果变成list,则效率底下。 我的intuitive的code class Solution(object): def reverse(...
Could the input string contain leading or trailing spaces? Yes. However, your reversed string should not contain leading or trailing spaces. How about multiple spaces between two words? Reduce them to a single space in the reversed string. SOLUTION 1: 1. 先处理原字符串: 使用strim把前后的空格...
344 Reverse String: https://leetcode.com/problems/reverse-string/description/ 541 Reverse String II: https://leetcode.com/problems/reverse-string-ii/description/ 题目&&解法: 1.Reverse String: Write a function that takes a string as input and returns the string reversed. Example: Given s = "...
344. 反转字符串 - 力扣(LeetCode) 代码随想录 解法1:双指针 因为while每次循环需要进行条件判断,而range函数不需要,直接生成数字,因此时间复杂度更低。推荐使用range class Solution: def reverseString(self, s: List[str]) -> None: """ Do not return anything, modify s in-place instead. """ n =...
3.调用C++ STL的方式,<algorithm>中有一个reverse函数,用于翻转各种可以使用双向迭代器的东西。代码如下: 1classSolution {2public:3stringreverseString(strings) {4reverse(&s[0],&s[s.length()]);5returns;6}7}; reverse函数介绍:http://zh.cppreference.com/w/cpp/algorithm/reverse ...
【LeetCode每天一题】Reverse String Write a function that reverses a string. The input string is given as an array of characterschar[].Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.You may assume all the ...
1classSolution {2public:3voidreverseString(vector<char>&s) {4if(s.size()==0)return;5intlength = s.size();//获取数组长度6char*front = &s[0];//获取数组第一个元素的地址7char*tail = &s[0];8for(inti =0,j=length-1; i <=length/2,j>= length /2;i++,j--)9{10swap(front[...
Example 1: Input:s = "IceCreAm" Output:"AceCreIm" Explanation: The vowels insare['I', 'e', 'e', 'A']. On reversing the vowels, s becomes"AceCreIm". Example 2: Input:s = "leetcode" Output:"leotcede" Constraints: 1 <= s.length <= 3 * 105 ...
链接:https://leetcode-cn.com/problems/reverse-words-in-a-string python # 翻转字符串里的单词 class Solution: def reverseWords(self, s: str)->str: """ 双指针,字符串的综合操作 解题思路如下: -1.移除多余空格 -1.1 rm开头空字符,遇空left指针++,遇非空停止 ...
0151-leetcode算法实现之翻转字符串里的单词-reverse-words-in-a-string-python&golang实现,给你一个字符串s,逐个翻转字符串中的所有单词。单词是由非空格字符组成的字符串。s中使用至少一个空格将字符串中的单词分隔开。请你返回一个翻转s中单词顺序并用单个空格相连的字