Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters. The input string does not contain leading or trailing spaces and the words are always separated by a single space. For example, Given s = "the sky is blue", return "blue ...
[LeetCode] 186. Reverse Words in a String II Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters. The input string does not contain leading or trailing spaces and the words are always separated by a single space. For example,...
Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters. The input string does not contain leading or trailing spaces and the words are always separated by a single space. For example, Given s = "the sky is blue", return "blue ...
leetcode[186]Reverse Words in a String II Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters. The input string does not contain leading or trailing spaces and the words are always separated by a single space. For example, Give...
这是一个关于Python的LeetCode题解,题目是186号题目:反转字符串中的单词。解题思路: 1. 首先,我们需要将输入的字符串按照空格分割成单词列表。 2. 然后,我们遍历这个单词列表,对于每个单词,我们将其首字母大写,其余字母小写,然后拼接起来,形成一个新的单词。
Leetcode: Reverse Words in a String 题目: Given an input string, reverse the string word by word. For example, Given s = “the sky is blue”, return “blue is sky the”. 思路一: 先休整下给定的字符串,去掉其中的多于一个的空格,就是使所有单词之间的空格都变成一个,然后去掉最后面的空格,...
https://leetcode.com/problems/reverse-words-in-a-string-ii/description/ 这道题我们首先想就是要把后面的...
反转可以用一个函数reverse实现。 找每个需要反转的单词可以通过双指针结合游标的方式实现。 public voidreverseWords(char[]str){if(str==null||str.length==0){return;}reverse(str,0,str.length-1);//寻找单词的双指针,i是游标int wordStart=0,wordEnd=0;for(int i=0;i<str.length;i++){if(str[i...
void reverseWords(string &s) { s = removeDuplicateSpace(s); int begin = 0; int end = 0; while(end < s.size()){ if(s[end] == ' '){ swapString(s, begin, end - 1); begin = end+1; end = begin; } else{ end++; } } swapString(s, begin, end - 1)...
输入:s = "a good example" 输出:"example good a" 解释:如果两个单词间有多余的空格,反转后的字符串需要将单词间的空格减少到仅有一个。 提示: 1 <= s.length <= 104 s 包含英文大小写字母、数字和空格 ' ' s 中至少存在一个 单词 进阶:如果字符串在你使用的编程语言中是一种可变数据类型,请尝试...