advanced point:regular expression"\\s+"can clean up redundancy blank. attention:if input is " ", the expect output is "". and the code is ok because of split("\s+"). 再介绍另一种方法,思路是先把整个串反转并且同时去掉多余的空格,然后再对反转后的字符串对其中的每个单词进行反转,比如"the ...
如下图所示,分隔" I love cmu "的结果是:"" "I" "love" "cmu" View Code GITHUB: https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/string/ReverseWords.java
Leetcode: Reverse Words in a String 题目: Given an input string, reverse the string word by word. For example, Given s = “the sky is blue”, return “blue is sky the”. 思路一: 先休整下给定的字符串,去掉其中的多于一个的空格,就是使所有单词之间的空格都变成一个,然后去掉最后面的空格,...
Output: "example good a" Explanation: You need to reduce multiple spaces between two words to a single space in the reversed string. Note: A word is defined as a sequence of non-space characters. Input string may contain leading or trailing spaces. However, your reversed string should not ...
Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". 注:该题目已有大神实现了,地址为 https://blog.csdn.net/lanxu_yy/article/details/38827845,但使用的是C++语言。
Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters. The input string does not contain leading or trailing spaces and the words are always separated by a single space. For example, ...
[LeetCode] 186. Reverse Words in a String II Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters. The input string does not contain leading or trailing spaces and the words are always separated by a single space....
[LeetCode]Reverse Words in a String Reverse Words in a String: Given an input string, reverse the string word by word. For example, Given s = “the sky is blue”, return “blue is sky the”. 把句子看做由词组成的,例如“A B C”,因此可以将句子的所有字符前后交换,得到“C’ B’ A...
Reduce them to a single space in the reversed string. 原问题链接:https://leetcode.com/problems/reverse-words-in-a-string/ 问题分析 这个问题的思路其实比较简单,因为它只是要把一个字符串里所有非空格的词语顺序给倒过来。那么我们就有这么一个基本的思路,首先将这个串按照空格给划分成多个非空的字符串。
Given an input string,reverse the string word by word.For example,Given s="the sky is blue",return"blue is sky the". 比较基础的一个题,拿到这个题,我的第一想法是利用vector来存每一个子串,然后在输出,这是一个比较简单的思路,此外,还有第二个思路,就是对所有的字符反转,然后在针对每一个子串反转...