自己的解法: 就是用一个StringBuffer来进行字符串的接收,利用一个指针来指示当前是哪一个k部分,当 i + k < s.length() 时,证明从 i 到 i + k - 1部分是可以进行反转的,而从i + k 部分到 i + 2 * k部分是直接进行拼接,利用条件 j < s.length()即可进行限制,不过对于最后剩余的一小部分如果是...
解法: classSolution{public:// method 1:stringreverseStr1(string s,intk){intsz = s.size();inti =0, j =0;boolflip =true; string res =""; string tmp ="";while(i < sz){while(j < sz && j < i + k){ j++; }if(flip){ tmp = s.substr(i, j-i); tmp =string(tmp.rbegin...
leetcode 541. Reverse String II 反转字符串 Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater ...
leetcode 541. Reverse String II Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than or equ...
Can you solve this real interview question? Reverse String - Write a function that reverses a string. The input string is given as an array of characters s. You must do this by modifying the input array in-place [https://en.wikipedia.org/wiki/In-place_a
19.Remove Nth Node From End of List删除链表的倒数第N个节点【LeetCode单题讲解系列】 图灵星球TuringPlanet 809 1 399.Evaluate Division除法求值【LeetCode单题讲解系列】 图灵星球TuringPlanet 2412 1 1055.Shortest Way to Form String 形成字符串的最短路径【LeetCode单题讲解系列】 图灵星球TuringPlanet 396...
新手村100题汇总:王几行xing:【Python-转码刷题】LeetCode 力扣新手村100题,及刷题顺序 读题 这题看着简单,那咱们就试试用 Python 最简单的方法求解。 1 Python 解法一:reverse 函数 ## LeetCode 344E - Reversing String, 简单做法 reverse from typing import List class Solution: def reverseString(self,...
Can you solve this real interview question? Reverse Words in a String III - Given a string s, reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: s = "Let's take
My code: 之前做过类似的题目,但是用了额外空间。 希望这周有好运。 Anyway, Good luck, Richardo! My code: 不知道为什么之前代码写...
反转可以用一个函数reverse实现。 找每个需要反转的单词可以通过双指针结合游标的方式实现。 public voidreverseWords(char[]str){if(str==null||str.length==0){return;}reverse(str,0,str.length-1);//寻找单词的双指针,i是游标int wordStart=0,wordEnd=0;for(int i=0;i<str.length;i++){if(str[i...