Reverse String II 自己的解法: 就是用一个StringBuffer来进行字符串的接收,利用一个指针来指示当前是哪一个k部分,当 i + k < s.length() 时,证明从 i 到 i + k - 1部分是可以进行反转的,而从i + k 部分到 i + 2 * k部分是直接进行拼接,利用条件 j < s.length()即可进行限制,不过对于最后剩...
classSolution{public:// method 1:stringreverseStr1(string s,intk){intsz = s.size();inti =0, j =0;boolflip =true; string res =""; string tmp ="";while(i < sz){while(j < sz && j < i + k){ j++; }if(flip){ tmp = s.substr(i, j-i); tmp =string(tmp.rbegin(), t...
具体代码如下: 1classSolution {2publicString reverseStr(String s,intk) {3char[] array =s.toCharArray();4for(inti = 0 ; i < s.length() ; i += 2*k ){5reverse(array,i,i+k-1);6}7returnString.valueOf(array);8}910privatevoidreverse(char[] array,intstart,intend) {11if( start >...
解法二: classSolution {public:stringreverseStr(strings,intk) {for(inti =0; i < s.size(); i +=2*k) { reverse(s.begin()+ i, min(s.begin() + i +k, s.end())); }returns; } }; 类似题目: Reverse String 参考资料: https://discuss.leetcode.com/topic/82652/one-line-c/2 http...
Leetcode 541. Reverse String II 原题链接:https://leetcode.com/problems/reverse-string-ii/description/ 描述: Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the......
题目给了我们一个string s 和 int k,让我们每次在2k 个 chars 里只反转 k 个chars。 利用Reverse String 里的 two pointers 来反转k 个chars,每一次增加 i by 2*k 就可以了。 具体请看code。 Java Solution: Runtime beats 67.31% 完成日期:04/07/2018 ...
541 Reverse String II: https://leetcode.com/problems/reverse-string-ii/description/ 题目&&解法: 1.Reverse String: Write a function that takes a string as input and returns the string reversed. Example: Given s = "hello", return "olleh". ...
LeetCode:Reverse String II 541. Reverse String II Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but ...
541. Reverse String II 旋转k个字符,然后间隔k个字符不旋转,再旋转k个字符。z 注意:一般最后都会剩下几个不够k个的字符,如果这些字符的前一次字符进行了旋转,就不旋转;如果前一次没有进行旋转,就需要旋转。其实就是奇数次旋转,偶数次不旋转 classSolution {public:stringreverseStr(strings,intk) {if(s.empty...
[LeetCode] 541. Reverse String II Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than or...