Given an input string, reverse the string word by word. For example, Given s = “the sky is blue”, return “blue is sky the”. 思路一: 先休整下给定的字符串,去掉其中的多于一个的空格,就是使所有单词之间的空格都变成一个,然后去掉最后面的空格,给最前面加一个空格。这样每次遇到空格的时候,前...
AI代码解释 voidreverseWords(string&s){string ss;int i=s.length()-1;while(i>=0){while(i>=0&&s[i]==' ')//处理多个空格的情况{i--;}if(i<0)break;if(ss.length()!=0)ss.push_back(' ');string temp;for(;i>=0&&s[i]!=' ';i--)temp.push_back(s[i]);reverse(temp.begin()...
return"blue is sky the". click to show clarification. Clarification: What constitutes a word? A sequence of non-space characters constitutes a word. Could the input string contain leading or trailing spaces? Yes. However, your reversed string should not contain leading or trailing spaces. How a...
Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". 解法一:全局翻转 局部翻转 核心代码 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 voidreverseWords(string &str) { if(str.size()==0)return; auto...
LeetCode之Reverse String 1、题目: Write a function that takes a string as input and returns the string reversed. Example: Given s = "hello", return "olleh". 2、代码实现: 代码实现1: public static String reverseString(String s) {...
输入:s = "the sky is blue" 输出:"blue is sky the" 示例2: 输入:s = " hello world " 输出:"world hello" 解释:反转后的字符串中不能存在前导空格和尾随空格。 示例3: 输入:s = "a good example" 输出:"example good a" 解释:如果两个单词间有多余的空格,反转后的字符串需要将单词间的空...
Can you solve this real interview question? Reverse Words in a String III - Given a string s, reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: s = "Let's take
return "blue is sky the". 注:该题目已有大神实现了,地址为 https://blog.csdn.net/lanxu_yy/article/details/38827845,但使用的是C++语言。 思路:大体为使用链表栈进行先进后出的操作方式。 直接上代码: /* Given an input string, reverse the string word by word. ...
题目:Reverse String(反转字符串) Write a function that reverses a string. The input string is given as an array of characterschar[]. Do not allocate extra space for another array, you must do this bymodifying the input array in-placewith O(1) extra memory. ...
| LeetCode:150. 逆波兰表达式求值,相信结合视频在看本篇题解,更有助于大家对本题的理解。 思路在上一篇文章中1047.删除字符串中的所有相邻重复项提到了 递归就是用栈来实现的。所以栈与递归之间在某种程度上是可以转换的! 这一点我们在后续讲解二叉树的时候, Scala TypeScript Swift Rust 7+ 36 5.4K 13宫...