先把整个数组reverse一下再逐个reverse单词。 具体采用two pointer 和 swap 的方法来reverse。 publicclassSolution {publicString reverseWords(String s) {if(s ==null)returnnull;char[] a =s.toCharArray();intn =s.length();//reverse the
用istringstream来读取string中的每一个word,然后对每一个word通过reverse函数反转。 代码如下: classSolution{public:stringreverseWords(strings){stringword;//hold every word in the stringstringret;istringstreamss(s);while(ss>>word){//read a wordreverse(word.begin(),word.end());//reverse itret = r...
Given a string, you need to reverse the order of characters in each word within a sentencewhilestill preserving whitespace and initial word order. Example1: Input:"Let's take LeetCode contest"Output:"s'teL ekat edoCteeL tsetnoc"Note: In the string, each word is separated by single sp...
Reverse Nodes in k-Group@LeetCode Reverse Nodes in k-Group 翻转链表的升级版,由于在以前阿里的面试中遇到过,所以特别在意,这次写题解之前又重新把原来通过的代码优化了一下。 其实这题很简单,知道了翻转链表的通用写法之后,解这一题其实就是循环翻转的过程(知道最后一个group长度不足)。 先介绍下翻转链表...
[LeetCode] Reverse Words in a String 翻转字符串中的单词 2015-06-29 08:14 −Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". Update (2015-02-... ...
Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". 并remove extra spaces Solution1:按char操作 思路:整体全部chars reverse + every words reverse Time Complexity: O(N) Space Complexity: O(N) 算返回的result ...
It will show the ammount of times every instruction was used, sorted by the most used ones. struct_hint infer what's the underlying structure used by a function. Highly heuristic. Don't trust it blindly, just try to use what it gives you and work from that. string_finder Utility to ...
public: string reverseWords(string s) { //两次翻转 int k=0; for(int i=0;i<s.size();i++) { while(i<s.size() && s[i]==' ') i++; //先去掉所有的空格 if(i==s.size()) break; int j=i; while(j<s.size() && s[j]!=' ') j++; ...
Reduce them to a single space in the reversed string. Solution: Reverse the whole string first, then reverse every single word. Redundant spaces must be skipped. Total time complexity is O(n). Space complexity is O(1). Accepted code: ...
Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc" ...