[LeetCode] Remove Duplicates from Sorted Array 有序数组中去除重复项 回到顶部 描述 Given a sorted arraynums, remove the duplicatesin-placesuch that each element appear onlyonceand return the new length. Do not allocate extra space for another array, you must do this by modifying the input arr...
} Remove Duplicates from Sorted Array II (Java) For example, given sorted array A = [1,1,1,2,2,3], your function should return length = 5, and A is now [1,1,2,2,3]. 最多允许两个重复,输出结果数组。 解法1:当counter是2时,就直接跳过即可,否则说明元素出现次数没有超,继续放入结果...
Given a sorted arraynums, remove the duplicatesin-placesuch that each element appear onlyonceand return the new length. Do not allocate extra space for another array, you must do this bymodifying the input arrayin-placewith O(1) extra memory. Example 1: Given nums = [1,1,2], Your fun...
Can you solve this real interview question? Remove Duplicates from Sorted Array - Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place [https://en.wikipedia.org/wiki/In-place_algorithm] such that each unique element
- LeetCodeleetcode.com/problems/remove-duplicates-from-sorted-array/description/ 解题思路 双指针 class Solution { public: int removeDuplicates(vector<int>& nums) { if(nums.size() == 0) return 0; int i = 0, j = 1; while(j < nums.size()) { if(nums[i] != nums[j]) { i+...
Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. ...
leetcode-26-Remove Duplicates from Sorted Array,Usesomethingliketwopointer,apointertoindicatecurrentposition,anothertoindicatenextfvector,wejust...
26. 删除有序数组中的重复项 - 给你一个 非严格递增排列 的数组 nums ,请你 原地 [http://baike.baidu.com/item/%E5%8E%9F%E5%9C%B0%E7%AE%97%E6%B3%95] 删除重复出现的元素,使每个元素 只出现一次 ,返回删除后数组的新长度。元素的 相对顺序 应该保持 一致 。然后返回 n
unique巧解 Jeremy_LeeL1发布于 2020-03-243.2kC++ 解题思路 这题其实可以直接用c++自带的unique函数,只要一行代码 代码 class Solution { public: int removeDuplicates(vector<int>& nums) { return unique(nums.begin(),nums.end())-nums.begin(); } }; ...
Do not allocate extra space for another array, you must do this bymodifying the input arrayin-placewith O(1) extra memory. 增加一个count来计数,从左至右遍历,遇到相同的直接del,否则count += 1 classSolution:defremoveDuplicates(self,nums):""" ...