}; 参考:https://leetcode.com/problems/remove-duplicates-from-sorted-list/discuss/1223275/Good-code-without-memory-leak-C%2B%2B-Ez-to-understnad
Github 同步地址: https://github.com/grandyang/leetcode/issues/83 类似题目: Remove Duplicates from Sorted List II Remove Duplicates From an Unsorted Linked List 参考资料: https://leetcode.com/problems/remove-duplicates-from-sorted-list/ https://leetcode.com/problems/remove-duplicates-from-sorted-l...
LeetCode: 82. Remove Duplicates from Sorted List II 题目描述 Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example, Given 1->2->3->3->4->4->5, return 1->2->5...
一是代表当前节点,二是对上一节点next的解引用。故为*list赋值即为给上一节点的next的赋值。
Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length.Do not allocate extra space for another array, you must do this by modifyi…
83. Remove Duplicates from Sorted List[值得review] Given a sorted linked list, delete all duplicates such that each element appear only once. For example, Given 1->1->2, return 1->2. Given 1->1->2->3->3, return 1->2->3.
https://leetcode.com/problems/remove-duplicates-from-sorted-list/description/ 解题思路: 判断前后两个node的val是否相等如果相等删除第二个, 如果不相等,对tempnode下移一位 代码: class Solution { public ListNode deleteDuplicates(ListNode head) {
83. 删除排序链表中的重复元素 - 给定一个已排序的链表的头 head , 删除所有重复的元素,使每个元素只出现一次 。返回 已排序的链表 。 示例 1: [https://assets.leetcode.com/uploads/2021/01/04/list1.jpg] 输入:head = [1,1,2] 输出:[1,2] 示例 2: [https
83. 删除排序链表中的重复元素 - 给定一个已排序的链表的头 head , 删除所有重复的元素,使每个元素只出现一次 。返回 已排序的链表 。 示例 1: [https://assets.leetcode.com/uploads/2021/01/04/list1.jpg] 输入:head = [1,1,2] 输出:[1,2] 示例 2: [https
Can you solve this real interview question? Remove Duplicates from Sorted List II - Given the head of a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. Return the linked list sorted