26. Remove Duplicates from Sorted Array 题目链接 思路一:单指针法,遍历数组,遇到和下一个元素不同的把这个元素按顺序保存到数组的前面,用指针记录保存的个数,注意数组只有一个元素和遍历到最后俩元素的特殊情况。 class Solution: def removeDuplicates(self,nums): sum = 0 if len(nums) <= 1: return 1 ...
https://oj.leetcode.com/problems/remove-duplicates-from-sorted-array/ 用一个cnt记录不重复的部分,后面每遇到不重复的cnt++即可。 classSolution {public:intremoveDuplicates(intA[],intn) {if(n==0)return0;intlast=A[0]-1;intcount=1;for(inti=0;i<n;i++){if(A[count-1]!=A[i]) { A[cou...
Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place such that each unique element appears only once. The relative order of the elements should be kept the same. Then return the number of unique elements in nums. Consider the number of unique elements of...
i++代码人生 Remove Duplicates from Sorted ArrayTotal Accepted:66627Total Submissions:212739My Submissions Given a sorted array, remove the duplicates in place such that each element appear onlyonceand return the new length. Do not allocate extra space for another array, you must do...
26. Remove Duplicates from Sorted Array(重要!) 一 once Do not allocate extra space for another array, you must do this in place with constant memory. For example, Given input array nums = [1,1,2],2, with the first two elements of nums being 1...
Can you solve this real interview question? Remove Duplicates from Sorted Array - Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place [https://en.wikipedia.org/wiki/In-place_algorithm] such that each unique element
给你一个非严格递增排列的数组nums,请你原地删除重复出现的元素,使每个元素只出现一次,返回删除后数组的新长度。元素的相对顺序应该保持一致。然后返回nums中唯一元素的个数。 考虑nums的唯一元素的数量为k,你需要做以下事情确保你的题解可以被通过: 更改数组nums,使nums的前k个元素包含唯一元素,并按照它们最初在num...
该题设部分有两个主要的关键点,其一是数组自身有顺序;其二是数组的本身返回仍是以袁数组nums的内容返回,预期不是采用新数组方式。 具体的一些复杂要求,可以去查看相关题设说明。 方法一: 使用双指针的方法,两个指针比较来进行移动. 其中i代表慢的指针,需要更新nums数组的值 ...
26. Remove Duplicates from Sorted Array 数组中重复元素的移除:要求空间复杂度是常量级的 我的第一个想法还是跟 27. Remove Element里面的第一个相同,遇到重复的就移动数组,把前面的重复值覆盖了,但是这样的时间复杂度比较大O(n2) 提交结果果然不尽人意 这时候脑子里的第一个反应就是肯定还有更快的,然后想法...
Array after removing duplicate elements: 1, 2, 3, 4, 5 Time Complexity: O(n), traversing through elements of the array.Space Complexity: O(n), using HashSet to store elements. Remove Duplicates from Array Using Sorting In this approach, we first sort the array. When sorted, duplicate el...