* Source : https://oj.leetcode.com/problems/remove-duplicates-from-sorted-array-ii/ * * * Follow up for "Remove Duplicates": * What if duplicates are allowed at most twice? * * For example, * Given sorted array A = [1,1,1,2,2,3], * * Your function should return length = 5...
1.思路:创建一个计数器来记录是否重复两次,创建一个指针来记录长度。 publicintremoveDuplicates(int[] nums) {if(nums.length==0)return0;intlength = 0;intcount = 1;for(inti = 1; i < nums.length; i++) {if(nums[i-1]!=nums[i]) { length++; nums[length]=nums[i]; count= 1; }elseif...
题目 Given a sorted array nums, remove the duplicates in-place such that duplicates appeared at most twice and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. Example 1: Given nums=[1,...
http://oj.leetcode.com/problems/remove-duplicates-from-sorted-array-ii/ 这道题跟Remove Duplicates from Sorted Array比較类似,差别仅仅是这里元素能够反复出现至多两次,而不是一次。事实上也比較简单。仅仅须要维护一个counter。当counter是2时,就直接跳过就可以,否则说明元素出现次数没有超,继续放入结果数组,若...
Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place such that each unique element appears only once. The relative order of the elements should be kept the same. Then return the number of unique elements in nums. Consider the number of unique elements of...
Can you solve this real interview question? Remove Duplicates from Sorted Array - Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place [https://en.wikipedia.org/wiki/In-place_algorithm] such that each unique element
数组——Remove Duplicates from Sorted Array 描述 Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory....
- LeetCodeleetcode.com/problems/remove-duplicates-from-sorted-array/description/ 解题思路 双指针 class Solution { public: int removeDuplicates(vector<int>& nums) { if(nums.size() == 0) return 0; int i = 0, j = 1; while(j < nums.size()) { if(nums[i] != nums[j]) { i+...
Type:mediun Given a sorted arraynums, remove the duplicatesin-placesuch that duplicates appeared at mosttwiceand return the new length. Do not allocate extra space for another array, you must do this bymodifying the input arrayin-placewith O(1) extra memory. ...
80. Remove Duplicates from Sorted Array II 总结:原地给列表去重,最多允许K个重复值。 解法: 1.快慢指针法(做差) 描述:慢指针i是每一个结果元素的索引,快指针n遍历所有列表元素。当索引i小于K时,前面最多有K个元素重复,满足要求,故i < K,可以直接填充元素。当前遍历的元素不等于当前i的前K个元素,因为当...