https://oj.leetcode.com/problems/remove-duplicates-from-sorted-array/ 用一个cnt记录不重复的部分,后面每遇到不重复的cnt++即可。 classSolution {public:intremoveDuplicates(intA[],intn) {if(n==0)return0;intlast=A[0]-1;intcount=1;for(inti=0;i<n;i++){if(A[count-1]!=A[i]) { A[cou...
Can you solve this real interview question? Remove Duplicates from Sorted Array - Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place [https://en.wikipedia.org/wiki/In-place_algorithm] such that each unique element
[LeetCode] Remove Duplicates from Sorted Array 有序数组中去除重复项 回到顶部 描述 Given a sorted arraynums, remove the duplicatesin-placesuch that each element appear onlyonceand return the new length. Do not allocate extra space for another array, you must do this by modifying the input arr...
Given a sorted arraynums, remove the duplicatesin-placesuch that each element appear onlyonceand return the new length. Do not allocate extra space for another array, you must do this bymodifying the input arrayin-placewith O(1) extra memory. Example 1: Given nums = [1,1,2], Your fun...
LeetCode_26_Remove Duplicates from Sorted Array 题目描述:给定一个整型数组,要求去除重复的数据,返回去重后的数组长度 method1:双指针(官方题解) 题目给定一个已经排好序的序列,我们可以设置双指针,一个slow指针,一个fast指针。fast指针用于跳过重复的数据,slow指针用于记录非重复的数据,即fast指针当前所指数据如果...
leetcode-26-Remove Duplicates from Sorted Array,Usesomethingliketwopointer,apointertoindicatecurrentposition,anothertoindicatenextfvector,wejust...
26. 删除有序数组中的重复项 - 给你一个 非严格递增排列 的数组 nums ,请你 原地 [http://baike.baidu.com/item/%E5%8E%9F%E5%9C%B0%E7%AE%97%E6%B3%95] 删除重复出现的元素,使每个元素 只出现一次 ,返回删除后数组的新长度。元素的 相对顺序 应该保持 一致 。然后返回 n
📺 视频题解📖 文字题解 方法一:双指针这道题目的要求是:对给定的有序数组 \textit{nums} 删除重复元素,在删除重复元素之后,每个元素只出现一次,并返回新的长度,上述操作必须通过原地修改数组的方法,使用 O(1) 的空间复杂度完成。由于给定的数组 \textit{nums} 是有序的,因此对于任 Python 双指针 JavaScrip...
Type:mediun Given a sorted arraynums, remove the duplicatesin-placesuch that duplicates appeared at mosttwiceand return the new length. Do not allocate extra space for another array, you must do this bymodifying the input arrayin-placewith O(1) extra memory. ...
Do not allocate extra space for another array, you must do this bymodifying the input arrayin-placewith O(1) extra memory. 增加一个count来计数,从左至右遍历,遇到相同的直接del,否则count += 1 classSolution:defremoveDuplicates(self,nums):""" ...