这道题给了我们一个数组,数组中的数字可能出现一次或两次,让我们找出所有出现两次的数字,由于之前做过一道类似的题目Find the Duplicate Number,所以不是完全无从下手。这类问题的一个重要条件就是1 ≤ a[i] ≤ n (n = size of array),不然很难在O(1)空间和O(n)时间内完成。首先来看一种正负替换的方法...
1classSolution2{3publicList<Integer> findDuplicates(int[] nums)4{5List<Integer> duplicates =newArrayList<>();67for(intnum: nums)8{9intabsNum =Math.abs(num);1011if(nums[absNum - 1] < 0)//if the number at position num - 1 is already negative12duplicates.add(absNum);//num is dupli...
Can you solve this real interview question? Find All Duplicates in an Array - Given an integer array nums of length n where all the integers of nums are in the range [1, n] and each integer appears at most twice, return an array of all the integers that
later scan again if at index i, A[i] != i+1, then A[i] is a duplicate 1publicclassSolution {2publicList<Integer> findDuplicates(int[] A) {3List<Integer> res =newArrayList<Integer>();4for(inti=0; i<A.length; i++) {5if(A[i]!=i+1 && A[i]!=A[A[i]-1]) {6inttemp ...
Contains Duplicate 题目Given an integer array nums, return true if any value appears at least twice in the array, and return false if every element is distinct. Example 1: Input: n…阅读全文 赞同 添加评论 分享收藏...
我的LeetCode代码仓:https://github.com/617076674/LeetCode 原题链接:https://leetcode-cn.com/problems/contains-duplicate-ii/description/ 题目描述: 知识点:哈希表、滑动窗口法 思路:滑动窗口法 本题是LeetCode217——存在重复元素的加强版,由于题目要求i... ...
j, count = 1, 1 # Start from the second element of the array and process # elements one by one. for i in range(1, len(nums)): # If the current element is a duplicate, # increment the count. if nums[i] == nums[i - 1]: count += 1 else: # Reset the count since we enc...
题目链接: https://leetcode-cn.com/problems/contains-duplicate/ 给定一个整数数组,判断是否存在重复元素。 如果任意一值在数组中出现至少两次,函数返回 true 。如果数组中每个元素都不相同,则返回 false 。 示例1: 代码语言:javascript 代码运行次数:0 ...
217. Contains Duplicate Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. ...
Note: You must not modify the array (assume the array is read only). You must use only constant, O(1) extra space. Your runtime complexity should be less than O(n2). There is only one duplicate number in the array, but it could be repeated more than once. ...