Can you solve this real interview question? Find All Duplicates in an Array - Given an integer array nums of length n where all the integers of nums are in the range [1, n] and each integer appears at most twice, return an array of all the integers that
一、题目 给定一个整数数组 a,其中1 ≤ a[i] ≤ n (n为数组长度), 其中有些元素出现两次而其他元素出现一次。 找到所有出现两次的元素。 你可以不用到任何额外空间并在O(n)时间复杂度内解决这个问题吗? 示例: 输入: [4,3,2,7,8,2,3,1] 输出: [2,3] 二、题解 解法1:哈希表 遍历给定数组时,...
Given an array of integers, 1 ≤ a[i] ≤n(n= size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime? Example: Input: [4,3,2,7,8,2,3,1] Output: [2...
Leetcode: Find All Duplicates in an Array Given an array of integers, 1 ≤ a[i] ≤ n (n =size of array), some elements appear twice and others appear once. Find all the elements that appear twice inthisarray. Could youdoit without extra space and in O(n) runtime?Example: Input: ...
442. Find All Duplicates in an ArrayMedium Topics Companies Given an integer array nums of length n where all the integers of nums are in the range [1, n] and each integer appears at most twice, return an array of all the integers that appears twice. You must write an algorithm that ...
详见:https://leetcode.com/problems/find-all-duplicates-in-an-array/description/ C++: 方法一: AI检测代码解析 classSolution{public:vector<int>findDuplicates(vector<int>&nums){vector<int>res;for(inti=0;i<nums.size();++i){intidx=abs(nums[i])-1;if(nums[idx]<0){res.push_back(idx+1);...
📺 视频题解📖 文字题解 方法一:双指针这道题目的要求是:对给定的有序数组 \textit{nums} 删除重复元素,在删除重复元素之后,每个元素只出现一次,并返回新的长度,上述操作必须通过原地修改数组的方法,使用 O(1) 的空间复杂度完成。由于给定的数组 \textit{nums} 是有序的,因此对于任 双指针 Python JavaScrip...
📺 视频题解📖 文字题解 方法一:双指针这道题目的要求是:对给定的有序数组 \textit{nums} 删除重复元素,在删除重复元素之后,每个元素只出现一次,并返回新的长度,上述操作必须通过原地修改数组的方法,使用 O(1) 的空间复杂度完成。由于给定的数组 \textit{nums} 是有序的,因此对于任 Python 双指针 JavaScrip...
Do not allocate extra space for another array, you must do this bymodifying the input arrayin-placewith O(1) extra memory. 给定一个排好序的数组,要求每个元素最多只能显示两次,返回删除超过两次显示的元素之后的数组。 设cur、tail两个指针,tail用来写新返回的数组。
Do not allocate extra space for another array, you must do this bymodifying the input arrayin-placewith O(1) extra memory. 增加一个count来计数,从左至右遍历,遇到相同的直接del,否则count += 1 classSolution:defremoveDuplicates(self,nums):""" ...