【LeetCode】Power of two 题目:Given an integer, write a function to determine if it is a power of two. 判断一个数是否为2的次方数。 对于这种玩数字的题目首先要考虑的是使用位操作来解决。 而java的位操作符为: 解法一: 2的次方数,只有首位为1 其它位都为0,可以通过位操作数来判断二
publicclassSolution{publicbooleanisPowerOfTwo(intn){if(n<=0)returnfalse;inti =0;intcountBit =0;while(i <32){if((n&(1<<i))!=0) countBit++; i++; }if(countBit !=1)returnfalse;returntrue; } } 算法时间 T(n)=O(1) 演示结果 publicstaticvoidmain(String [] args){intn =4; Solu...
LeetCode 342: 4 的幂 时间复杂度:O(1) 只需要使用常数次位运算和布尔运算 空间复杂度:O(1) 只需要使用常数个额外变量即可 代码(Python3) class Solution: def isPowerOfTwo(self, n: int) -> bool: # 非正数一定不是 2 的幂次方 if n <= 0: return False return (n & (n - 1)) == 0 ...
Can you solve this real interview question? Power of Two - Given an integer n, return true if it is a power of two. Otherwise, return false. An integer n is a power of two, if there exists an integer x such that n == 2x. Example 1: Input: n = 1 Ou
LeetCode Top Interview Questions 231. Power of Two (Java版; Easy) 题目描述 Given an integer, write a function to determine if it is a power of two. Example 1: Input: 1 Output: true Explanation: 20 = 1 Example 2: Input: 16
算法细节系列(2):231.Power of Two && Three 前言 在刷leetCode时,遇到了一系列关于power of Number的问题,刚开始不以为然,以为用简单的递归就能求解,可直到看到power of three官方解时,才发现自己的渺小。它的思维深度和广度着实不是我等小菜能够比拟的,但我还是在其基础上强行解释了一些算法的核心思想。
leetcode231. Power of Two 题目要求 Given an integer, write a function to determine if it is a power of two. 判断一个整数是否是2的幂。 思路和代码 当我们从二进制的角度来看,这个题目就非常简单了。其实题目的要求等价于该整数对应的二进制数中,一共有几个1。该题目的难点在于考虑边界情况,比如-2...
Leetcode力扣1418 手画图解版|点菜展示表 Display table of food order in restaurant 爱学习的饲养员 2442 1 Leetcode 231 2的幂 书森学院 65 1 Leetcode力扣239.滑动窗口最大值 丶mars_ 3481 3 Leetcode 231. Power of Two (Python) Myron_yoo 21 0 Leetcode刷题 2 两数相加 Add Two Numbers...
Can you solve this real interview question? Reordered Power of 2 - You are given an integer n. We reorder the digits in any order (including the original order) such that the leading digit is not zero. Return true if and only if we can do this so that t
简介:Given an integer, write a function to determine if it is a power of two.Credits: Special thanks to @jianchao.li.fighter for adding this problem and creating all test cases.如果是power of Given an integer, write a function to determine if it is a power of two. ...