classSolution{publicbooleanisPowerOfTwo(intx){returnx >0&& (x ==1|| (x %2==0&& isPowerOfTwo(x /2))); } } Python 实现(递归) classSolution:defisPowerOfTwo(self, x):""" :type n: int :rtype: bool """returnx >0and(x ==1o
LeetCode 326: 3 的幂 LeetCode 342: 4 的幂 时间复杂度:O(1) 只需要使用常数次位运算和布尔运算 空间复杂度:O(1) 只需要使用常数个额外变量即可 代码(Python3) class Solution: def isPowerOfTwo(self, n: int) -> bool: # 非正数一定不是 2 的幂次方 if n <= 0: return False return (n ...
Power of Two 题目: Given an integer, write a function to determine if it is a power of two. class Solution(object): def isPowerOfTwo(self, n): # """ :type n: int :rtype: bool """ 方法:分析2的幂次方的特点,发现2的任意次方的数,化成二进制时只有首位为1其余位为0,因此我的解决方...
题目地址:https://leetcode.com/problems/reordered-power-of-2/description/ 题目描述 Starting with a positive integer N, we reorder the digits in any order (including the original order) such that the leading digit is not zero. Return true if and only if we can do this in a...
leetcode.com/problems/power-of-three/ 2.1)采用循环 class Solution: def isPowerOfThree(self, n: int) -> bool: if not n: return False while n: if n==1: return True if n%3: return False n //=3 return True Runtime: 80 ms, faster than 52.08% of Python3 online submissions...
LeetCode笔记:326. Power of Three 大意: 给出一个整数,写一个函数来判断它是否是3的次方数。 进阶: 你能不能不用循环和递归来做? 思路: 一开始看这个题目没明白是什么意思,后来查了一下才知道是判断是否3的次方数,所谓次方数就是n个3相乘得出的数咯,总是容易想到立方上去。这个题其实最简单的就是不断...
Power of Two 判断是否为2的次方 Power of Two Given an integer, write a function to determine if it is a power of two. Credits: Special thanks to @.fighter for adding this problem and creating all test cases. class Solution {...
My Solutions to Leetcode problems. All solutions support C++ language, some support Java and Python. Multiple solutions will be given by most problems. Enjoy:) 我的Leetcode解答。所有的问题都支持C++语言,一部分问题支持Java语言。近乎所有问题都会提供多个算
My Solutions to Leetcode problems. All solutions support C++ language, some support Java and Python. Multiple solutions will be given by most problems. Enjoy:) 我的Leetcode解答。所有的问题都支持C++语言,一部分问题支持Java语言。近乎所有问题都会提供多个算法解决。大家加油!:) 0 stars 721 forks ...
boolean startsWith(CString prefix)检查字符串是否以指定字符串开头boolean endsWith(CString suffix)检查字符串是否以指定字符串结尾int indexOf(CString str,int fromIndex)从指定位置开始,返回指定字符串在字符串中第一次出现的位置... 字符串函数 replace replace()返回一个字符串,其中原始字符串中指定字符串的...