https://leetcode.com/problems/power-of-two/discuss/63974/Using-nand(n-1)-trick https://leetcode.com/problems/power-of-two/discuss/63972/One-line-java-solution-using-bitCount LeetCode All in One 题目讲解汇总(持续更新中...)
https://leetcode.com/problems/reordered-power-of-2/discuss/149843/C%2B%2BJavaPython-Straight-Forward https://leetcode.com/problems/reordered-power-of-2/discuss/151949/Simple-Java-Solution-Based-on-String-Sorting [LeetCode All in One 题目讲解汇总(持续更新中...)](https://www.cnblogs.com/gran...
leetcode 231. Power of Two 判断是否为2的幂 Given an integer, write a function to determine if it is a power of two. 译:给定一个整数,写一个能判断是否为2的次方的方法。 实现 public class Solution { public boolean isPowerOfTwo(int n) { return (n > 0) && ((n &am......
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My Solutions to Leetcode problems. All solutions support C++ language, some support Java and Python. Multiple solutions will be given by most problems. Enjoy:) 我的Leetcode解答。所有的问题都支持C++语言,一部分问题支持Java语言。近乎所有问题都会提供多个算法解决。大家加油!:) 0 stars 721 forks ...
[leetcode]326. Power of Three problem 326. Power of Three solution: Iteration AI检测代码解析 class Solution { public: bool isPowerOfThree(int n) { if(n<1) return false;//err. while(n%3==0) { n /= 3; } return n==1;//err....
power-of-two class Solution { public: bool isPowerOfTwo(int n) { return n>=1 && !(n&(n-1)); } }; n=10000***000, <=> n&(n-1)=0 是这种方法的核心 https://leetcod i++ 版本号 c++ 链表 转载 mob604756f261ee 2017-05-27 14:27:00 175阅读 2评论 Power of Four https...
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Leetcode 231: Power of Two Given an integer, write a function to determine if it is a power of two. 1 public class Solution { 2 public bool IsPowerOfTwo(int n) { 3 if (n <= 0) return false; 4 if (n <= 2) return true; 5 6 while (n > 2) 7 { 8 if (n % 2 != ...
Reference: https://leetcode.com/problems/reordered-power-of-2/discuss/149843/C%2B%2BJavaPython-Straight-Forward__EOF__ 本文作者:Veritas des Liberty 本文链接:https://www.cnblogs.com/h-hkai/p/10897015.html关于博主:评论和私信会在第一时间回复。或者直接私信我。版权声明:本博客所有文章除特别声明...