下面是思路 https://leetcode-cn.com/problems/decode-ways/solution/mmplao-niang-zhong-yu-xie-chu-lai-liao-by-vegetabl/ 下面是代码(使用了特殊条件的判断) https://leetcode-cn.com/problems/decode-ways/solution/dong-tai-gui-hua-java-python-by-liweiwei1419/ 四. 图常用算法 最小生成树算法 Prim算法 Kruskal算法 最短路径 DinkStra Floyd算...
class Solution { public: vector<int> sortArray(vector<int>& nums) { // bubbleSort int n = nums.size(); for (int i = 0; i < n - 1; ++i) { bool flag = false; for (int j = 0; j < n - 1 - i; ++j) { if (nums[j] > nums[j + 1]) { swap(nums[j], nums[j ...
学习JAVA的教学资料:LeetCode前400题Java精美版.pdf,LEETCODE 题目精选 Selected Solutions 1.00 Felomeng Contents 1. Two Sum Easy 1 2. Add Two Numbers Medium 1 3. Longest Substring Without Repeating Characters Medium 2 4. Median of Two Sorted Arrays Hard 2 5
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* }*/importjava.util.HashMap;publicclassSolution {publicintmaxPoints(Point[] points) {if(points.length<=1)returnpoints.length;intmax = 0;for(inti =0;i<points.length;i++){ HashMap<Double, Integer> map =newHashMap<Double, Integer>();intsameX =1, sameP =0;for(intj =0;j<points.le...
java leetcode dsa Updated Jun 2, 2025 Java garyellow / LC-GFG-solution Star 1 Code Issues Pull requests A LeetCode a day keeps the boring away (๑•̀ㅂ•́)و✧ cplusplus leetcode geeksforgeeks leetcode-solutions geeksforgeeks-solutions Updated Jun 2, 2025 C++ thr...
1. Description: Notes: 2. Examples: 3.Solutions: 1/**2* Created by sheepcore on 2018-11-113*/4classSolution {5publicString[] reorderLogFiles(String[] logs) {6Comparator<String> myComp =newComparator<String>() {7@Override8publicintcompare(String s1, String s2) {9ints1si = s1.indexOf...
public class Solution { public String reverseWords(String s) { // 使用trim()方法去除字符串前后的空格 s = s.trim(); // 使用StringBuilder来存储结果,避免频繁的字符串拼接操作 StringBuilder sb = new StringBuilder(); // 定义一个双指针,分别指向字符串的开头和末尾 int start = 0; int end = s...
Java: class Solution { public int mySqrt(int x) { if (x <= 1) { return x; } double l = 0; double r = 1; while (l != r) { l = r; r = (r + x / r) / 2; } return (int)r; } } 300. 最长递增子序列 (medium) 动画过大,点击查看 方法1.动态规划 思路:dp[i]表示...