学习了一个更简洁的(https://leetcode.com/discuss/45017/5-lines-o-1-space%26time-c-solution-no-hash) 自己优化了一下 一行代码AC。 classSolution {public:boolisPowerOfTwo(intn) {returnn<=0?false: !(n & (n-1)); } };
classSolution(object): defisPowerOfTwo(self, n): """ :type n: int :rtype: bool """ #-4??? c=0 whilen >0: ifn &1: c+=1 n >>=1 returnc==1 标签:leetcode 好文要顶关注我收藏该文微信分享 bonelee 粉丝-897关注 -1
leetcode 231. Power of Two 判断是否为2的幂 Given an integer, write a function to determine if it is a power of two. 译:给定一个整数,写一个能判断是否为2的次方的方法。 实现 public class Solution { public boolean isPowerOfTwo(int n) { return (n > 0) && ((n &am......
整理自leetCode 231.Power of Two && 236.Power of Three Given an integer, write a function to determine if it is a power of two. Given an integer, write a function to determine if it is a power of three. Follow up: Could you do it without using any loop / recursion? 常规解题手段:...
leetcode.com/problems/power-of-three/ 2.1)采用循环 class Solution: def isPowerOfThree(self, n: int) -> bool: if not n: return False while n: if n==1: return True if n%3: return False n //=3 return True Runtime: 80 ms, faster than 52.08% of Python3 online submissions...
AI代码解释 publicclassSolution{publicbooleanisPowerOfFour(int num){// 转化为二进制数来判断if(num<0)returnfalse;String binaryStr=Integer.toBinaryString(num);for(int i=0;i<binaryStr.length();i++){if(i==0&&binaryStr.charAt(i)!='1')returnfalse;elseif(i>0&&binaryStr.charAt(i)!='0')...
power of two power-of-two class Solution { public: bool isPowerOfTwo(int n) { return n>=1 && !(n&(n-1)); } }; n=10000***000, <=> n&(n-1)=0 是这种方法的核心 https://leetcod i++ 版本号 c++ 链表 转载 mob604756f261ee 2017-05-27 14:27:00 162阅读 2评论 Power ...
My Solutions to Leetcode problems. All solutions support C++ language, some support Java and Python. Multiple solutions will be given by most problems. Enjoy:) 我的Leetcode解答。所有的问题都支持C++语言,一部分问题支持Java语言。近乎所有问题都会提供多个算法解决。大家加油!:) 0 stars 721 forks ...
power-of-two class Solution { public: bool isPowerOfTwo(int n) { return n>=1 && !(n&(n-1)); } }; n=10000***000, <=> n&(n-1)=0 是这种方法的核心 https://leetcod i++ 版本号 c++ 链表 转载 mob604756f261ee 2017-05-27 14:27:00 175阅读 2评论 Power of Four https...
/// Source : https://leetcode.com/problems/add-to-array-form-of-integer/ /// Author : liuyubobobo /// Time : 2019-02-13 #include <iostream> #include <vector> using namespace std; /// Array and number addition /// Time Complexity: O(n) /// Space Complexity: O(...