输入:s = "ADOBECODEBANC", t = "ABC"输出:"BANC"解释:最小覆盖子串 "BANC" 包含来自字符串 t 的 'A'、'B' 和 'C'。 示例2: 输入:s = "a", t = "a"输出:"a"解释:整个字符串 s 是最小覆盖子串。 示例3: 输入:s = "a", t = "aa"输出:""解释:t 中两个字符 'a' 均应包含在 ...
https://leetcode.com/problems/valid-word-abbreviation/description/ https://leetcode.com/problems/generalized-abbreviation/description/ 唯一需要注意的是,需要返回最短的长度,而最短的长度中数字只算一个长度,例如 the abbreviation "a32bc" has length = 4, 因为“32”长度算1. 因此定义一个class node, ...
Given a target string and a set of strings in a dictionary, find an abbreviation of this target string with thesmallest possiblelength such that it does not conflict with abbreviations of the strings in the dictionary. Each number or letter in the abbreviation is considered length = 1. For e...
//这个是超时的代码publicstaticintminRectanglesToCoverPoints(int[][]points,int w){Arrays.sort(points,(a,b)->a[0]-b[0]);int cnt=1;int n=points.length;for(int i=0;i<n;i++){for(int j=i+1;j<n;j++){if(points[j][0]-points[i][0]<=w){continue;}else{cnt++;i=j;}}}retu...
Explanation: The median of the array is already equal tok. Constraints: 1 <= nums.length <= 2 * 105 1 <= nums[i] <= 109 1 <= k <= 109 --- 中位数是正中间的数, 那么就要先排序, 然后去判断中位数跟k的大小, 如果k<中位数, 那么就要去遍历中位数前面的数字,因为前面的数字是可能大...
length() < t.length()) { return ""; } //用来统计t中每个字符出现次数 int[] needs = new int[128]; //用来统计滑动窗口中每个字符出现次数 int[] window = new int[128]; for (int i = 0; i < t.length(); i++) { needs[t.charAt(i)]++; ...
Leetcode solution 243: Shortest Word Distance 2019-12-26 03:41 −Problem Statement Given a list of words and two words word1 and word2, return the shortest distance between these two word... 包子模拟面试 0 210 【leetcode】1289. Minimum Falling Path Sum II ...
publicintfindMin(int[]nums){if(nums.length==1){returnnums[0];}intleft=0;intright=nums.length-1;while(left<right){int middle=left+(right-left)/2;// 不能选和left比,因为如果整个数组升序就会错过min的值// 就是找到分裂的位置,mid和最右边比,如果mid大就说明在分裂的左边,那么就应该移动左边/...
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将S,T里字符换成String,变成Leetcode 30, Substring with Concatenation of All Words. You are given a string, s, and a list of words, words, that are all of the same length. Find all starting indices of substring(s) in s that is a concatenation of each word in words exactly once and...