classSolution{public:intmaxScoreWords(vector<string>& words, vector<char>& letters, vector<int>& score){intres =0, n = words.size(), m =1<< n;vector<int>count(26);for(charc : letters) ++count[c -'a'];for(intmask =0; mask < m; ++mask) {intsum =0, isValid =1; vector<...
Return the maximum score of any valid set of words formed by using the given letters (words[i]cannot be used two or more times). It is not necessary to use all characters inlettersand each letter can only be used once. Score of letters'a','b','c', ... ,'z'is given byscore[0...
输入:nums1 = [2,4,5,8,10], nums2 = [4,6,8,9] 输出:30 解释:合法路径包括: [2,4,5,8,10], [2,4,5,8,9], [2,4,6,8,9], [2,4,6,8,10],(从 nums1 开始遍历) [4,6,8,9], [4,5,8,10], [4,5,8,9], [4,6,8,10] (从 nums2 开始遍历)最大得分为上图中的...
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The score after splitting a string is the number of zeros in the left substring plus the number of ones in the right substring. Example 1: Input: s = "011101" Output: 5 Explanation: All possible ways of splitting s into two non-empty substrings are: left = "0" and right = "11101...
LeetCode Contest 186 5392. 分割字符串的最大得分 Maximum Score After Splitting a String Table of Contents 一、中文版 二、英文版 三、My answer 四、解题报告 一、中文版 给你一个由若干 0 和 1 组成的字符串 s ,请你计算并返回将该字符串分割成两个 非空 子字符串(即左 子字符串和 右 子字符...
Can you solve this real interview question? Maximum Score of a Node Sequence - There is an undirected graph with n nodes, numbered from 0 to n - 1. You are given a 0-indexed integer array scores of length n where scores[i] denotes the score of node i. Y
Given a string s of zeros and ones, return the maximum score after splitting the string into two non-empty substrings (i.e. left substring and right substring). The score after splitting a string is the number of zeros in the left substring plus the number of ones in the right substring...
60 changes: 60 additions & 0 deletions60Maximum Sum Score of Array/kata.go Original file line numberDiff line numberDiff line change @@ -0,0 +1,60 @@ packageMaximum_Sum_Score_of_Array import"math" funcmaximumSumScore(nums[]int)int64{ ...
1537. 最大得分 - 你有两个 有序 且数组内元素互不相同的数组 nums1 和 nums2 。 一条 合法路径 定义如下: * 选择数组 nums1 或者 nums2 开始遍历(从下标 0 处开始)。 * 从左到右遍历当前数组。 * 如果你遇到了 nums1 和 nums2 中都存在的值,那么你可以切换路径到