Leetcode 34. Find First and Last Position of Element in Sorted Array 在一个有序数组中找到第一个和最后一个元素 解决思路: 利用二分法来进行位置的查找,主要涉及两个函数int lower_bound(nums, target) 和 int upper_bound(nums, target); 分别找到target的第一个和最后一个位置。 其中主要有一下几个方...
}String[] arr = s.split(" ");returnarr[arr.length-1].length(); } 04 第三种解法 将原字符串首尾的空格去掉,然后找到最后一次出现空格的位置,两者相减再减1即为最后单词的长度。 public intlengthOfLastWord3(String s) { return s.trim().length()-s.trim().lastIndexOf(" ")-1; } 05 小结...
58. Length of Last Word【leetcode】 Given a stringsconsists of upper/lower-case alphabets and empty space characters' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space chara...
class Solution { public int lengthOfLastWord(String s) { //思路:获取去掉起始和结束的空格后字符串的长度len_strim,获取最后一次出现空格的位置loc,思考所求的最后一个单词的长度与len_strim和loc的关系,result=len_strim-loc-1 int len_strim=s.trim().length(); int loc=s.trim().lastIndexOf("...
intlengthOfLastWord(char*s){intlength;//数组长度intnum=0;//返回最后一个单词的长度inti,j;length=strlen(s);for(i=0;i<length;i++){//建议当不是空格时计数 避免全空格if(s[i]!=' '){num=0;for(j=i;j<length&&s[j]!=' ';j++){//计算单词长度 始终记录最后一个单词num++;}i=j;//...
Note: A word is defined as a character sequence consists of non-space characters only. For example, Given s = “Hello World”, return 5. 题很简单,直接上代码吧! 代码如下: public class Solution { public int lengthOfLastWord(String s) ...
Given a string s consists of some words separated by spaces, return the length of the last word in the string. If the last word does not exist, return 0. A word is a maximal substring consisting of non-space characters only. 1.2 中文题目 ...
Can you solve this real interview question? Length of Last Word - Given a string s consisting of words and spaces, return the length of the last word in the string. A word is a maximal substring consisting of non-space characters only. Example 1:
Length of Last Word Introduce Given a string s consists of upper/lower-case alphabets and empty space characters ’ ', return the length of last word in the string. If the last word does not exist, return 0. Note: A...LeetCode 58:Length of Last Word Given a string s consists of...
LeetCode : Length of Last Word Given a string s consists of upper/lower-case alphabets and empty space characters ’‘, return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space ...