Can you solve this real interview question? Shortest Completing Word - Given a string licensePlate and an array of strings words, find the shortest completing word in words. A completing word is a word that contains all the letters in licensePlate. Igno
Find the minimum length word from a given dictionarywords, which has all the letters from the stringlicensePlate. Such a word is said to complete the given stringlicensePlate Here, for letters we ignore case. For example,"P"on thelicensePlatestill matches"p"on the word. It is guaranteed a...
(Easy) Shortest Completing Word - LeetCode Description: Find the minimum length word from a given dictionarywords, which has all the letters from the stringlicensePlate. Such a word is said tocompletethe given stringlicensePlate Here, for letters we ignore case. For example,"P"on thelicensePl...
View Code solution2: 参考 1. Leetcode_easy_748. Shortest Completing Word; 2. Grandyang; 完
748. Shortest Completing Word* 748. Shortest Completing Word* https://leetcode.com/problems/shortest-completing-word/ 题目描述 Find the minimum length word from a given dictionary words, which has all the letters from the string licens......
https://leetcode.com/problems/shortest-completing-word/ 题目描述 Find the minimum length word from a given dictionary words, which has all the letters from the string licensePlate. Such a word is said to complete the given string lic...
package leetcode import "unicode" func shortestCompletingWord(licensePlate string, words []string) string { lp := genCnter(licensePlate) var ret string for _, w := range words { if match(lp, w) { if len(w) < len(ret) || ret == "" { ret = w } } } return ret } func gen...
Can you solve this real interview question? Shortest Completing Word - Given a string licensePlate and an array of strings words, find the shortest completing word in words. A completing word is a word that contains all the letters in licensePlate. Igno
classSolution {public:stringshortestCompletingWord(stringlicensePlate, vector<string>&words) { map<int, vector<string>>m; vector<char>chars;for(stringword : words) { m[word.size()].push_back(word); }for(charc : licensePlate) {if(c >='a'&& c <='z') chars.push_back(c);elseif(c...
LeetCode算法题-Shortest Completing Word(Java实现) 这是悦乐书的第309次更新,第330篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第178题(顺位题号是748)。从给定的字典单词中查找最小长度单词,其中包含字符串licensePlate中的所有字母。据说这样的单词可以完成给定的字符串licensePlate。在这里,...