代码参考:https://leetcode.com/problems/length-of-last-word/discuss/21892/7-lines-4ms-C%2B%2B-Solution
Given a string s consists of some words separated by spaces, return the length of the last word in the string. If the last word does not exist, return 0. A word is a maximal substring consisting of non-space characters only. 1.2 中文题目 给你一个字符串 s,由若干单词组成,单词之间用空格...
https://github.com/grandyang/leetcode/issues/58 参考资料: https://leetcode.com/problems/length-of-last-word/ https://leetcode.com/problems/length-of-last-word/discuss/21927/My-3-line-0-ms-java-solution https://leetcode.com/problems/length-of-last-word/discuss/21892/7-lines-4ms-C%2B%...
L58: Length of Last Word Given a string s consists of upper/lower-case alphabets and empty space characters ’‘, return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space characters ...
[LeetCode]58.Length of Last Word 题目Given a string s consists of upper/lower-case alphabets and empty space characters ’‘, return the length of last word in the string. If the last word does not exist, return 0. Note: A ... ...
If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space characters only. For example, Given s = "Hello World", return 5. My Solution public class Solution { public static int lengthOfLastWord(String s) { ...
class Solution{public:intlengthOfLastWord(string s){if(s.empty())return0;if(s.size()==1)return1;intcount=0;bool flag=true;// 从后面开始,遇到空格就跳过,知道遇到第一个字母,开始计数,再遇到空格就breakfor(inti=s.size()-1;i>=0;--i){if(s[i]==' '){if(!flag)break;}else{++count...
说明:一个单...[LeetCode] Length of Last Word - 最后一个单词的长度 题目概述: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is d......
class Solution { public int lengthOfLastWord(String s) { //思路:获取去掉起始和结束的空格后字符串的长度len_strim,获取最后一次出现空格的位置loc,思考所求的最后一个单词的长度与len_strim和loc的关系,result=len_strim-loc-1 int len_strim=s.trim().length(); int loc=s.trim().lastIndexOf("...
【摘要】 这是一道关于最后一个单词长度的LeetCode题目,希望对您有所帮助。 题目概述: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. ...