代码参考:https://leetcode.com/problems/length-of-last-word/discuss/21892/7-lines-4ms-C%2B%2B-Solution
leetcode length of the last word Given a stringsconsists of upper/lower-case alphabets and empty space characters' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space characters...
1.1 英文题目 Given a string s consists of some words separated by spaces, return the length of the last word in the string. If the last word does not exist, return 0. A word is a maximal substring consisting of non-space characters only. 1.2 中文题目 给你一个字符串 s,由若干单词组成,...
public: int lengthOfLastWord(string s) { stringstream ss(s); string word; while(ss>>word); return word.size(); } }; 1. 2. 3. 4. 5. 6. 7. 8. 9.
Can you solve this real interview question? Length of Last Word - Given a string s consisting of words and spaces, return the length of the last word in the string. A word is a maximal substring consisting of non-space characters only. Example 1:
字母序连续字符串是由字母表中连续字母组成的字符串。换句话说,字符串"abcdefghijklmnopqrstuvwxyz"的任意子字符串都是字母序连续字符串。 例如,"abc"是一个字母序连续字符串,而"acb"和"za"不是。 给你一个仅由小写英文字母组成的字符串s,返回其最长的 字母序连续子字符串 的长度。
[LeetCode]58.Length of Last Word 题目Given a string s consists of upper/lower-case alphabets and empty space characters ’‘, return the length of last word in the string. If the last word does not exist, return 0. Note: A ... ...
【CSON】LeetCode:718. Maximum Length of Repeated Subarray 0播放 · 总弹幕数02022-03-10 11:15:04 主人,未安装Flash插件,暂时无法观看视频,您可以… 下载Flash插件 点赞 投币收藏分享 稿件投诉 未经作者授权,禁止转载 官方网站:www.cspiration.com 微信号:cspiration01 微信公众号:北美CS求职 ...
If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space characters only. For example, Given s = "Hello World", return 5. My Solution public class Solution { public static int lengthOfLastWord(String s) { ...
LeetCode 58: Length of Last Word 題目描述 題目說明:給一個字串,裡面可能包含英文字母(alphabets) 與空格(space)。回傳最後一個單字(word)的長度。 例如: "Hello World ", 應回傳 5, 因為 World 的長度為 5。 TDD 開始 Step 1, 新增測試用例。長度為2, 不含空格的 word。 s 為"bc" ...