第一步:start_times[0] = 0 < end_times[0] = 10,需要新的房间,所以current_rooms = 1。然后start_pointer加一。 第二步:start_times[1] = 5 < end_times[0] = 10,又有一个新的会议开始,需要另一个房间,所以current_rooms = 2。然后start_pointer再次加一。 第三步:start_times[2] = 15不小于...
1classSolution {2publicintminMeetingRooms(int[][] intervals) {3//corner case4if(intervals ==null|| intervals.length == 0) {5return0;6}78//normal case9Arrays.sort(intervals, (a, b) -> a[0] - b[0]);10//sort by ending time11PriorityQueue<int[]> heap =newPriorityQueue<>(intervals...
时间复杂度为O(NlogN)。 /** * Definition for an interval. * struct Interval { * int start; * int end; * Interval() : start(0), end(0) {} * Interval(int s, int e) : start(s), end(e) {} * };*/classSolution {public:intminMeetingRooms(vector<Interval>&intervals) { typedef...
* Interval(int s, int e) : start(s), end(e) {} * };*/classSolution {public:staticboolcmp(Interval &a, Interval &b){if(a.start==b.start)returna.end<b.end;returna.start<b.start; }intminMeetingRooms(vector<Interval>&intervals) { sort(intervals.begin(),intervals.end(),cmp); pr...
252. Meeting Rooms的拓展,同样给一个开会的区间数组,返回最少需要的房间数。 解法1: 把区间变成2个数组:start时间数组和end时间数组,并对两个数组排序。然后一个指针遍历start数组,另一个指针指向end数组。如果start时间小于end时间,房间数就加1,start时间加1,比较并记录出现过的最多房间数。start时间大于end,则...
Code classSolution:defminMeetingRooms(self, intervals: List[List[int]]) ->int: intervals.sort(key=lambdax: x[0]) free_rooms=[]fors, einintervals:iffree_roomsands >=free_rooms[0]: heapq.heappop(free_rooms) heapq.heappush(free_rooms, e)returnlen(free_rooms)...
classSolution {public:intminMeetingRooms(vector<vector<int>>&intervals) { sort(intervals.begin(), intervals.end(), [](constvector<int>& a,constvector<int>& b){returna[0] < b[0];}); priority_queue<int, vector<int>, greater<int>>pq;for(auto interval : intervals){if(!pq.empty() ...
LeetCode 253. Meeting Rooms II 原题链接在这里:https://leetcode.com/problems/meeting-rooms-ii/ 题目: Given an array of meeting time intervals consisting of start and end times[[s1,e1],[s2,e2],...](si < ei), find the minimum number of conference rooms required....
https://github.com/grandyang/leetcode/issues/253 类似题目: Merge Intervals Meeting Rooms 参考资料: https://leetcode.com/problems/meeting-rooms-ii/ https://leetcode.com/problems/meeting-rooms-ii/discuss/67857/AC-Java-solution-using-min-heap ...
leetcode253 - Meeting Rooms II - medium Given an array of meeting time intervals consisting of start and end times [[s1,e1],[s2,e2],...] (si < ei), find the minimum number of conference rooms required. Example 1: Input: [[0, 30],[5, 10],[15, 20]]...