heappush(free_rooms, intervals[0][1]) # 从第二个会议开始遍历 for i in intervals[1:]: # 如果当前会议的开始时间大于等于最小堆中的最早结束时间 # 说明这个会议室可以被重复使用 # 因此我们可以移除堆顶元素(最早结束的会议室) if i[0] >= free_rooms[0]: heapq.heappop(free_rooms) # 将当前...
[LeetCode] Meeting Rooms Problem Description: Given an array of meeting time intervals consisting of start and end times[[s1,e1],[s2,e2],...](si < ei), determine if a person could attend all meetings. For example, Given[[0, 30],[5, 10],[15, 20]], returnfalse. The idea is p...
// Step 3: Scan the events and maintain the number of meeting rooms in use. int maxRooms = 0; int roomsInUse = 0; for (int[] event : events) { // Update the number of rooms in use roomsInUse += event[1]; // Update the maximum number of rooms needed maxRooms = Math.max(...
Github 同步地址: https://github.com/grandyang/leetcode/issues/252 类似题目: Merge Intervals Meeting Rooms II 参考资料: https://leetcode.com/problems/meeting-rooms/ https://leetcode.com/problems/meeting-rooms/discuss/67782/C%2B%2B-sort https://leetcode.com/problems/meeting-rooms/discuss/67786/...
题目地址:https://leetcode-cn.com/problems/meeting-rooms/ 题目描述 Given an array of meeting time intervals consisting of start and end times[[s1,e1],[s2,e2],...] (si < ei), find the minimum number of conference rooms required. ...
[Leetcode] Meeting Rooms 会议室 Meeting Rooms Given an array of meeting time intervals consisting of start and end times[[s1,e1],[s2,e2],...] (si < ei), determine if a person could attend all meetings. For example, Given[[0, 30],[5, 10],[15, 20]], return false....
leetcode 数组专题 06-leetcode.253 meeting room ii 力扣.253 会议室 II 题目 给你一个会议时间安排的数组 intervals ,每个会议时间都会包括开始和结束的时间 intervals[i] = [starti, endi] ,返回 所需会议室的最小数量 。 示例1: 输入:intervals = [[0,30],[5,10],[15,20]] ...
Leetcode Meeting room问题系列 - 2 上面四类咋解决呢,我发现有共同的思路。 首先就是按照start开始升排序,因为时间有先后循序。 sort_list = sorted(lst_time, key = lambda x: x.start) 定义时间集合list的长度为len_t, 然后循环去取里面的元素(len_t -1个元素),这个元素的end与后面元素的start比较,...
0252-Meeting-Rooms 0253-Meeting-Rooms-II/cpp-0253 CMakeLists.txt main.cpp main2.cpp main3.cpp main4.cpp 0254-Factor-Combinations 0257-Binary-Tree-Paths 0259-3Sum-Smaller 0268-Missing-Number 0279-Perfect-Squares 0282-Expression-Add-Operators 0283-Move-Zeroes 0286-Walls-and...
使用扫描线算法 来解决 Leetcode 253 - 会议室 II 的问题,是一种非常巧妙且高效的方法。 这个方法的核心思想是将所有的会议事件(开始和结束)转化为事件点,然后按时间顺序处理这些事件,模拟会议室的使用情况。 思路: 事件拆分:对于每个会议 interval[i] = [starti, endi],我们将其拆解为两个事件: 开始事件:表...