[LeetCode] Meeting Rooms Problem Description: Given an array of meeting time intervals consisting of start and end times[[s1,e1],[s2,e2],...](si < ei), determine if a person could attend all meetings. For example, Given[[0, 30],[5, 10],[15, 20]], returnfalse. The idea is p...
Github 同步地址: https://github.com/grandyang/leetcode/issues/252 类似题目: Merge Intervals Meeting Rooms II 参考资料: https://leetcode.com/problems/meeting-rooms/ https://leetcode.com/problems/meeting-rooms/discuss/67782/C%2B%2B-sort https://leetcode.com/problems/meeting-rooms/discuss/67786/...
public class Solution { public int minMeetingRooms(Interval[] intervals) { if(intervals == null || intervals.length == 0) return 0; Arrays.sort(intervals, new Comparator<Interval>(){ public int compare(Interval i1, Interval i2){ return i1.start - i2.start; } }); // 用堆来管理房...
heappush(free_rooms, intervals[0][1]) # 从第二个会议开始遍历 for i in intervals[1:]: # 如果当前会议的开始时间大于等于最小堆中的最早结束时间 # 说明这个会议室可以被重复使用 # 因此我们可以移除堆顶元素(最早结束的会议室) if i[0] >= free_rooms[0]: heapq.heappop(free_rooms) # 将当前...
// The room count will be the number of rooms we need return roomCount + 1; // We need at least one room } } 代码解释: 排序: 我们将所有的会议的开始时间和结束时间分别存入startTimes和endTimes数组,并对这两个数组进行排序。这样,我们可以确保在处理会议时,始终按顺序处理会议的开始和结束时间。
题目地址:https://leetcode-cn.com/problems/meeting-rooms/ 题目描述 Given an array of meeting time intervals consisting of start and end times[[s1,e1],[s2,e2],...] (si < ei), find the minimum number of conference rooms required. ...
则可以复用房间if(startTimes[i]>=endTimes[endIndex]){// Reuse the room: move the endIndex to the next meetingendIndex++;}else{// If no room is available, we need a new oneroomCount++;}}// The room count will be the number of rooms we needreturnroomCount+1;// We need at least...
meeting room II : greedy algorithm and compare function question: Given an array of meeting time intervals consisting of start and end times [[s1,e1],[s2,e2],...] (si < ei), find the minimum number of conference rooms required. For exampl......
0252-Meeting-Rooms 0253-Meeting-Rooms-II/cpp-0253 CMakeLists.txt main.cpp main2.cpp main3.cpp main4.cpp 0254-Factor-Combinations 0257-Binary-Tree-Paths 0259-3Sum-Smaller 0268-Missing-Number 0279-Perfect-Squares 0282-Expression-Add-Operators 0283-Move-Zeroes 0286-Walls-and...
题目描述 题目描述 题解 提交记录 提交记录 代码 排序 不限 登录并分享题解 登录 9 1 2 › [[0,30],[5,10],[15,20]] [[7,10],[2,4]] Source 该题目是 Plus 会员专享题 感谢使用力扣!您需要升级为 Plus 会员来解锁该题目 升级Plus 会员...