第一步:start_times[0] = 0 < end_times[0] = 10,需要新的房间,所以current_rooms = 1。然后start_pointer加一。 第二步:start_times[1] = 5 < end_times[0] = 10,又有一个新的会议开始,需要另一个房间,所以current_rooms = 2。然后start_pointer再次加一。 第三步:start_times[2] = 15不小于...
// Step 3: Scan the events and maintain the number of meeting rooms in use. int maxRooms = 0; int roomsInUse = 0; for (int[] event : events) { // Update the number of rooms in use roomsInUse += event[1]; // Update the maximum number of rooms needed maxRooms = Math.max(...
Given an array of meeting time intervals consisting of start and end times[[s1,e1],[s2,e2],...](si < ei), find the minimum number of conference rooms required. For example, Given[[0, 30],[5, 10],[15, 20]], return2. 思路:贪心。 将所有interval按照开始时间从早到晚排序。之后依次...
* };*/classSolution {public:boolcmp(Interval &a, Interval &b){if(a.start==b.start)returna.end<b.end;returna.start<b.start; }intminMeetingRooms(vector<Interval>&intervals) { map<int,int>m;for(auto x:intervals){++m[x.start];--m[x.end]; }introoms=0, res=0;for(auto x:m){...
return2. Link: https://leetcode.com/problems/meeting-rooms-ii/description/ 解题方法: 先记录每个interval开始和结束所需要的房间数,当开始时,需要的房间数为1,而结束时,需要的房间数为-1; 再遍历一遍以上记录的数组,这样所需的房间数会随着以上的记录不断的变化,用一个变量去记录随时变化的房间数出现的最...
则可以复用房间if(startTimes[i]>=endTimes[endIndex]){// Reuse the room: move the endIndex to the next meetingendIndex++;}else{// If no room is available, we need a new oneroomCount++;}}// The room count will be the number of rooms we needreturnroomCount+1;// We need at least...
题目地址:https://leetcode-cn.com/problems/meeting-rooms/ 题目描述 Given an array of meeting time intervals consisting of start and end times[[s1,e1],[s2,e2],...] (si < ei), find the minimum number of conference rooms required. ...
[Leetcode] Meeting Rooms 会议室 Meeting Rooms Given an array of meeting time intervals consisting of start and end times[[s1,e1],[s2,e2],...] (si < ei), determine if a person could attend all meetings. For example, Given[[0, 30],[5, 10],[15, 20]], return false....
0252-Meeting-Rooms 0253-Meeting-Rooms-II/cpp-0253 CMakeLists.txt main.cpp main2.cpp main3.cpp main4.cpp 0254-Factor-Combinations 0257-Binary-Tree-Paths 0259-3Sum-Smaller 0268-Missing-Number 0279-Perfect-Squares 0282-Expression-Add-Operators 0283-Move-Zeroes 0286-Walls-and...
题目描述 题目描述 题解 提交记录 提交记录 代码 排序 不限 登录并分享题解 登录 9 1 2 › [[0,30],[5,10],[15,20]] [[7,10],[2,4]] Source 该题目是 Plus 会员专享题 感谢使用力扣!您需要升级为 Plus 会员来解锁该题目 升级Plus 会员...