Leetcode No.169 Majority Element(c++实现) 1. 题目 1.1 英文题目 Given an array nums of size n, return the majority element. The majority element is the element that appears more than ⌊n / 2⌋ times. You may assume that the majority element always exists in the array. 1.2 中文题目 ...
2.hash 遍历数组,利用hash方式记录元素出现的次数,当某个元素次数超过⌊n/2⌋时,即为我们要找的。 View Code(28ms) 3.sorting 对数组进行排序,由于要找的元素超过半数,所以下标n/2的元素一定是它,这里总数奇偶不影响,可以自己举例验证一下。 classSolution {public:intmajorityElement(vector<int>&nums) {...
Given an array nums of size n, return the majority element. The majority element is the element that appears more than ⌊n / 2⌋ times. You may assume that the majority element always exists in the array. 1.2 中文题目 给定一个大小为 n 的数组,找到其中的多数元素。多数元素是指在数组中...
impl Solution { pub fn majority_element(nums: Vec<i32>) -> i32 { // 维护 majority ,表示众数 let mut majority = 0; // 维护 count ,表示当前众数的个数 let mut count = 0; // 遍历每个数 for num in nums { // 如果当前众数的个数为 0 ,则更新当前众数为 num if count == 0 { majo...
[LeetCode]Majority Element Question Given an array of size n, find the majority element. The majority element is the element that appearsmore than⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array....
原帖连接:https://leetcode.com/discuss/19151/solution-computation-space-problem-can-extended-situation http://m.blog.csdn.net/blog/wenyusuran/40780253 解决方案: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 classSolution{public:intmajorityElement(vector<int>&nums){int size=nums.size();int vot...
这道题出现在了王道的《2019数据结构考研复习指导》的18页,LeetCode中也有这道题。题目大意是:给定一个长度为n的数组,我们定义"主元素"为数组中出现次数超过⌊n/2⌋的元素。 Description Given an array of size n, find the majority element. The majority element is the element that appears more than...
The majority element of a subarray is an element that occurs threshold times or more in the subarray. Implementing the MajorityChecker class: MajorityChecker(int[] arr) Initializes the instance of the class with the given array arr. int query(int left, int right, int threshold) returns the ...
intmajorityElement(vector<int> &num) { intn = num.size(); sort(num.begin(),num.end()); returnnum[n/2]; } }; public class Solution { public int MajorityElement(int[] nums) { Array.Sort(nums); return nums[nums.Length/2]; ...
https://leetcode.com/discuss/19151/solution-computation-space-problem-can-extended-situation http://m.blog.csdn.net/blog/wenyusuran/40780253 解决方案: classSolution{public:intmajorityElement(vector<int>& nums){intsize = nums.size();intvote =0;intcount =0;for(inti =0;i < size;i++) ...