https://leetcode.com/problems/majority-element/discuss/51613/O(n)-time-O(1)-space-fastest-solution https://leetcode.com/problems/majority-element/discuss/51612/6-Suggested-Solutions-in-C++-with-Explanations https://leetcode.com/problems/majority-element/discuss/51611/Java-solutions-(sorting-hashma...
最后,再统计一次候选众数在数组中出现的次数,若满足要求,则返回之。 代码: publicclassSolution {publicList<Integer> majorityElement(int[] nums) { List<Integer> list =newArrayList<Integer>();if(nums ==null|| nums.length == 0)returnlist;intn =nums.length;intcount = n/3;intnum1 = nums[0];...
Given an array of sizen, find the majority element. The majority element is the element that appears more than⌊ n/2 ⌋times. You may assume that the array is non-empty and the majority element always exist in the array. 第一中方案如下:比较通用的一种解法,也比较笨 public class Solut...
C++ 智能模式 1 2 3 4 5 6 class Solution { public: vector<int> majorityElement(vector<int>& nums) { } }; 已存储 行1,列 1 运行和提交代码需要登录 Case 1Case 2Case 3 nums = [3,2,3] 1 2 3 [3,2,3] [1] [1,2] Source ...
[LeetCode]Majority Element II Question Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 本题难度Medium。 投票法...
原帖连接:https://leetcode.com/discuss/19151/solution-computation-space-problem-can-extended-situation http://m.blog.csdn.net/blog/wenyusuran/40780253 解决方案: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 classSolution{public:intmajorityElement(vector<int>&nums){int size=nums.size();int vot...
169.Majority Element Hash 首先想到的就是Hash表,但是并不满足Follow up 用Java写了一版: classSolution{publicintmajorityElement(int[]nums){Map<Integer,Integer>map=newHashMap<Integer,Integer>();for(Integernum:nums){if(map.containsKey(num)){Integercnt=map.get(num)+1;map.put(num,cnt);}else{map...
Majority Element Majority Element 今天是一到有关数学计算的题目,较为简单,来自LeetCode,难度为Easy,Acceptance为37.5%。 题目如下 Given an array of sizen, find the majority element. The majority element is the element that appears more thann/2times....
这道题出现在了王道的《2019数据结构考研复习指导》的18页,LeetCode中也有这道题。题目大意是:给定一个长度为n的数组,我们定义"主元素"为数组中出现次数超过⌊n/2⌋的元素。 Description Given an array of size n, find the majority element. The majority element is the element that appears more than...
classSolution { public: intmajorityElement(vector<int> &num) { intn = num.size(); sort(num.begin(),num.end()); returnnum[n/2]; } }; public class Solution { public int MajorityElement(int[] nums) { Array.Sort(nums); return nums[nums.Length/2]; ...