classSolution{publicintmajorityElement(int[] nums){intmajorityCount=nums.length /2;for(intnum1 : nums) {intcount=0;for(intnum2 : nums) {if(num2 == num1) { ++count; } }if(count > majorityCount) {returnnum1; } }thrownewIllegalArgumentException("The array does not contain a majority...
方法3,采用随机选取元素的方法,进行统计: 1#definerandom(x) (rand()%x)2classSolution {3public:4intmajorityElement(vector<int> &num) {56intresult;7while(1)8{9result=num[random(num.size())];10intcount=0;11for(inti=0;i<num.size();i++)12{13if(num[i]==result)14{15count++;16}17}...
impl Solution { pub fn majority_element(nums: Vec<i32>) -> i32 { // 维护 majority ,表示众数 let mut majority = 0; // 维护 count ,表示当前众数的个数 let mut count = 0; // 遍历每个数 for num in nums { // 如果当前众数的个数为 0 ,则更新当前众数为 num if count == 0 { majo...
Given an array of size n, find the majority element. The majority element is the element that appearsmore than⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 本题难度Easy。有3种算法分别是:哈希法、排序法...
原帖连接:https://leetcode.com/discuss/19151/solution-computation-space-problem-can-extended-situation http://m.blog.csdn.net/blog/wenyusuran/40780253 解决方案: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 classSolution{public:intmajorityElement(vector<int>&nums){int size=nums.size();int vot...
[LeetCode]Majority Element II Question Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 本题难度Medium。 投票法...
classSolution:defmajorityElement(self,nums):returncollections.Counter(nums).most_common(1)[0][0] 排序 时间:O(nlogn) 空间:O(nlogn) 如果自己编写堆排序,则只需要使用O(1)的额外空间 classSolution{publicintmajorityElement(int[]nums){Arrays.sort(nums);returnnums[nums.length/2];}} ...
Majority Element Majority Element 今天是一到有关数学计算的题目,较为简单,来自LeetCode,难度为Easy,Acceptance为37.5%。 题目如下 Given an array of sizen, find the majority element. The majority element is the element that appears more thann/2times....
这道题出现在了王道的《2019数据结构考研复习指导》的18页,LeetCode中也有这道题。题目大意是:给定一个长度为n的数组,我们定义"主元素"为数组中出现次数超过⌊n/2⌋的元素。 Description Given an array of size n, find the majority element. The majority element is the element that appears more than...
intmajorityElement(vector<int> &num) { intn = num.size(); sort(num.begin(),num.end()); returnnum[n/2]; } }; public class Solution { public int MajorityElement(int[] nums) { Array.Sort(nums); return nums[nums.Length/2]; ...