LeetCode题解---Majority Element II 摩尔投票法 题目描述: Given an integer array of sizen, find all elements that appear more than⌊ n/3 ⌋times. The algorithm should run in linear time and in O(1) space. 分析: 因为要找出的是出现次数大于⌊ n/3 ⌋的元素,因此最多只可能存在两个...
169. Majority Element的拓展,这题要求的是出现次数大于n/3的元素,并且限定了时间和空间复杂度,因此不能排序,不能使用哈希表。 解法:Boyer-Moore多数投票算法Boyer–Moore majority vote algorithm,T:O(n) S: O(1) 摩尔投票法 Moore Voting Java: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18...
Majority Element II Description Note: Example 1 Example 2 Solution 1(C++) 算法分析 排序,然后计算相邻元素相同的次数,如果超过len/3就可以添加到res中,否则不添加。 程序分析 略。...leetcode 229. Majority Element II leetcode 229. Majority Element II 题意:给你一个数组,让你找出里面出现次数大于[...
169 classSolution:defmajorityElement(self,nums:List[int])->int:current=0count=0foriinrange(len(nums)):ifnums[i]==nums[current]:count+=1else:count-=1ifcount==0:current=icount=1returnnums[current] 229 class Solution: def majorityElement(self, nums: List[int]) -> List[int]: current1,...
实现代码 C++: classSolution{public:vector<int>majorityElement(vector<int>& nums){ vector<int> res;intm =0, n =0, cm =0, cn =0;for(inti =0; i < nums.size(); i++) {if(nums[i] == m) { cm++; }elseif(nums[i] == n) ...
[LeetCode]Majority Element II Question Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 本题难度Medium。 投票法...
[LeetCode] Majority Element II 简介:Well, this problem becomes a little trickier since there may be more than one majority element. But, there can be at most two of them. Well, this problem becomes a little trickier since there may be more than one majority element. But, there can be ...
【LeetCode题解】169_求众数(Majority-Element) 目录169_求众数(Majority-Element) 描述 解法一:暴力法 思路 Java 实现 Python 实现 复杂度分析 解法二:哈希表 思路 Java 实现 Python 实现 复杂度分析 解法三:排序 Java 实现 Python 实现 复杂度分析 解法四:随机选择【待完成】 思路 Java实现 Python 实现 ...
class Solution { public: int majorityElement(vector<int>& nums) { return majority(nums, 0, nums.size() - 1); } private: int majority(vector<int>& nums, int left, int right) { if (left == right) return nums[left]; int mid = left + ((right - left) >> 1); int lm = major...
[LeetCode]Majority Element Question Given an array of size n, find the majority element. The majority element is the element that appearsmore than⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array....