putVal(hash(key), key, value, false, evict); } } } 存储: put调用的HashMap的put方法,调用两个空方法,由LinkedHashMap实现 public V put(K key, V value) { return putVal(hash(key), key, value, false, true); } final V putVal(int hash, K key, V value, boolean onlyIfAbsent, boolean...
LinkedHashMap没有提供remove方法,所以调用的是HashMap的remove方法,实现如下: public V remove(Object key) { Entry<K,V> e = removeEntryForKey(key); return (e == null ? null : e.value); } final Entry<K,V> removeEntryForKey(Object key) { int hash = (key == null) ? 0 : hash(key...
publicVput(K key, Vvalue){// 对key为null的处理if(key ==null)returnputForNullKey(value);// 计算hashinthash = hash(key);// 得到在table中的indexinti = indexFor(hash, table.length);// 遍历table[index],是否key已经存在,存在则替换,并返回旧值for(Entry<K,V> e = table[i]; e !=null...
LinkedHashMap没有提供remove方法,所以调用的是HashMap的remove方法,实现如下: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 public V remove(Object key) { Entry<K,V> e = removeEntryForKey(key); return (e == null ? null : e.value); } final Entry<K,V> removeEntryForKey(Object key)...
* 而是直接通过双向链表遍历Map中的所有key-value映射, */publicbooleancontainsValue(Object value){// Overridden to take advantage of faster iteratorif(value==null) {for(Entrye=header.after; e != header; e = e.after)if(e.value==null)returntrue; ...
* map acts like a normal map - the eldest element is never removed). * * @param eldest The least recently inserted entry in the map, or if * this is an access-ordered map, the least recently accessed * entry. This is the entry that will be removed it this ...
* Returns <tt>true</tt> if this map should remove its eldest entry. * This method is invoked by <tt>put</tt> and <tt>putAll</tt> after * inserting a new entry into the map. It provides the implementor * with the opportunity to remove the eldest entry each time a new one ...
lm.modCount++;//移除当前访问的Entryremove();//将当前访问的Entry插入到链表的尾部addBefore(lm.header); } } LinkedHashMap重写了HashMap中的recordAccess方法(HashMap中该方法为空),当调用父类的put方法时,在发现key已经存在时,会调用该方法;当调用自己的get方法时,也会调用到该方法。
The set supports element removal, which removes the corresponding mapping from the map, via the Iterator.remove, Set.remove, removeAll, retainAll and clear operations. It does not support the add or addAll operations. Its Spliterator typically provides faster sequential performance but much poorer ...
throw new NoSuchElementException(); current = e; next = e.after; return e; } //移除结点 current public final void remove() { Node<K,V> p = current; if (p == null) throw new IllegalStateException(); if (modCount != expectedModCount) throw new Concurren...