LinkedHashMap.Entry<K,V> e = next;if(modCount != expectedModCount)thrownewConcurrentModificationException();if(e ==null)thrownewNoSuchElementException(); current = e; next = e.after;//依次迭代returne; } } 自此已经大致清楚了LinkedHashMap是如何简单的改造了HashMap而拥有了顺序的迭代。 LinkedH...
putVal(hash(key), key, value, false, evict); } } } 存储: put调用的HashMap的put方法,调用两个空方法,由LinkedHashMap实现 public V put(K key, V value) { return putVal(hash(key), key, value, false, true); } final V putVal(int hash, K key, V value, boolean onlyIfAbsent, boolean...
publicVput(K key, Vvalue){// 对key为null的处理if(key ==null)returnputForNullKey(value);// 计算hashinthash = hash(key);// 得到在table中的indexinti = indexFor(hash, table.length);// 遍历table[index],是否key已经存在,存在则替换,并返回旧值for(Entry<K,V> e = table[i]; e !=null...
LinkedHashMap没有提供remove方法,所以调用的是HashMap的remove方法,实现如下: public V remove(Object key) { Entry<K,V> e = removeEntryForKey(key); return (e == null ? null : e.value); } final Entry<K,V> removeEntryForKey(Object key) { int hash = (key == null) ? 0 : hash(key...
* Returns <tt>true</tt> if this map should remove its eldest entry. * This method is invoked by <tt>put</tt> and <tt>putAll</tt> after * inserting a new entry into the map. It provides the implementor * with the opportunity to remove the eldest entry each time a new one ...
LinkedHashMap没有提供remove方法,所以调用的是HashMap的remove方法,实现如下: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 public V remove(Object key) { Entry<K,V> e = removeEntryForKey(key); return (e == null ? null : e.value); } final Entry<K,V> removeEntryForKey(Object key)...
if(removeEldestEntry(eldest)) {removeEntryForKey(eldest.key); }else{//扩容到原来的2倍if(size>= threshold)resize(2* table.length); } }voidcreateEntry(inthash, Kkey, V value,intbucketIndex) {// 向哈希表中插入Entry,这点与HashMap中相同//创建新的Entry并将其链入到数组对应桶的链表的头结点...
If the map is modified while an iteration over the set is in progress (except through the iterator's own remove operation, or through the setValue operation on a map entry returned by the iterator) the results of the iteration are undefined. The set supports element removal, which removes ...
throw new NoSuchElementException(); Entry<K,V> e = lastReturned = nextEntry; nextEntry = e.after; return e; } } // Key 迭代器,KeySet private class KeyIterator extends LinkedHashIterator<K> { public K next() { return nextEntry().getKey(); } ...
Simply put, any access operation on the map results in an order such that the element that was accessed would appear last if an iteration were to be carried out right away. After the above examples, it should be obvious that aputAlloperation generates one entry access for each of the mappi...